For the truss shown , The strength of the truss is assumed to be governed by the strength of member BC. Use Fy = 248 MPa and E = 200 GPa. The member BC is composed of two angular sections placed back-to-back separated by s = 8 mm as shown. If a = 4 meters, Properties of 75 x 75 x 12 mm angle A = 1774 mm² Ix = 0.92 x 10^6 mm^4 Iy = 0.92 x 10^6 mm^4 x = y = 23.25 mm 1. Using LRFD, which of the ff. most nearly gives the value of P in kiloNewtons. 2.Using LRFD, which of the ff. most nearly gives the reaction at D kiloNewtons. 3. Using ASD, which of the ff. most nearly gives the design strength of member BC in kiloNewtons.
For the truss shown , The strength of the truss is assumed to be governed by the strength of member BC. Use Fy = 248 MPa and E = 200 GPa. The member BC is composed of two angular sections placed back-to-back separated by s = 8 mm as shown. If a = 4 meters, Properties of 75 x 75 x 12 mm angle A = 1774 mm² Ix = 0.92 x 10^6 mm^4 Iy = 0.92 x 10^6 mm^4 x = y = 23.25 mm 1. Using LRFD, which of the ff. most nearly gives the value of P in kiloNewtons. 2.Using LRFD, which of the ff. most nearly gives the reaction at D kiloNewtons. 3. Using ASD, which of the ff. most nearly gives the design strength of member BC in kiloNewtons.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
For the truss shown , The strength of the truss is assumed to be governed by the strength of member BC. Use Fy = 248 MPa and E = 200 GPa. The member BC is composed of two angular sections placed back-to-back separated by s = 8 mm as shown. If a = 4 meters,
Properties of 75 x 75 x 12 mm angle
A = 1774 mm²
Ix = 0.92 x 10^6 mm^4
Iy = 0.92 x 10^6 mm^4
x = y = 23.25 mm
1. Using LRFD, which of the ff. most nearly gives the value of P in kiloNewtons.
2.Using LRFD, which of the ff. most nearly gives the reaction at D kiloNewtons.
3. Using ASD, which of the ff. most nearly gives the design strength of member BC in kiloNewtons.
Transcribed Image Text:2.5P
30°
30°
1.5P
a
45°
A
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