For the transistor circuit shown below, what is the value of the base current? Vcc = +18 V V₂. 21.625 μα B) 18.873 μA 21.392 ΝΑ 18.994 μA RB1 39 kn C₁ DE 10 μF RB2 8.2 ΚΩ 18 Rele 3.3 ΚΩ C → В MA + V BE E + V CE RE C₂ He 10 μF 1 kn B = 120 CE 50 μF OF •Vo H ***

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
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For the transistor circuit shown below, what is the value of the base current?
Vcc = +18 V
V₂.
A) 21.625 μA
B) 18.873 μA
21.392 ΝΑ
18.994 μA
RB1
39 ΚΩ
C₁
ĐI
10 μF
R52
8.2 kn
1B
Rc
3.3 ΚΩ
→ B
+
VBE E
V CE
RE
C₂
HE
10 μF
1 ΚΩ
V
B = 120
OF
H
+₁
50 μF
Transcribed Image Text:For the transistor circuit shown below, what is the value of the base current? Vcc = +18 V V₂. A) 21.625 μA B) 18.873 μA 21.392 ΝΑ 18.994 μA RB1 39 ΚΩ C₁ ĐI 10 μF R52 8.2 kn 1B Rc 3.3 ΚΩ → B + VBE E V CE RE C₂ HE 10 μF 1 ΚΩ V B = 120 OF H +₁ 50 μF
For the transistor circuit shown below, what is the value of the emitter current?
Vcc = +18 V
Rc
3.3 ΚΩ
B
Vi
A) 1.732 mA
B) 2.21 MA
2.3 mA
(D) 1.752 mA
R01
39 ΚΩ
C₁
11=₂
10 μF
RB2
8.2 ΚΩ
18
C
MA
+
VBE E
+
C₂
HG
10 μF
+
V CE
RE
1 ΚΩ
V
B = 120
CE
50 μF
AF
***
Transcribed Image Text:For the transistor circuit shown below, what is the value of the emitter current? Vcc = +18 V Rc 3.3 ΚΩ B Vi A) 1.732 mA B) 2.21 MA 2.3 mA (D) 1.752 mA R01 39 ΚΩ C₁ 11=₂ 10 μF RB2 8.2 ΚΩ 18 C MA + VBE E + C₂ HG 10 μF + V CE RE 1 ΚΩ V B = 120 CE 50 μF AF ***
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