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For the titration of 30.00mL of 0.120M aqueous solution of ammonia (NH3) with 0.200MHCI, calculate the pH at the equivalence point. The K of ammonia is 1.80 × 10 . Please show your work. b -5 1. For the titration of 30.00 mL of 0.120 M aqueous solution of ammonia (NH3) with 0.200 M HCI, calculate the pH at the equivalence point. The Kb of ammonia is 1.80 x10-5. Please show your work. 23 SA NH + HCI == сітлений Hy .ROM - 03 =

For the titration of 30.00mL of 0.120M aqueous solution of ammonia (NH3) with 0.200MHCI, calculate the pH at the equivalence point. The K of ammonia is 1.80 × 10 . Please show your work. b -5 1. For the titration of 30.00 mL of 0.120 M aqueous solution of ammonia (NH3) with 0.200 M HCI, calculate the pH at the equivalence point. The Kb of ammonia is 1.80 x10-5. Please show your work. 23 SA NH + HCI == сітлений Hy .ROM - 03 =

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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For the titration of 30.00mL of 0.120M aqueous solution of ammonia (NH3) with 0.200MHCI, calculate the pH at the equivalence point. The K of ammonia is 1.80 × 10 . Please show your work. b -5 1. For the titration of 30.00 mL of 0.120 M aqueous solution of ammonia (NH3) with 0.200 M HCI, calculate the pH at the equivalence point. The Kb of ammonia is 1.80 x10-5. Please show your work. 23 SA NH + HCI == сітлений Hy .ROM - 03 =
Transcribed Image Text:For the titration of 30.00mL of 0.120M aqueous solution of ammonia (NH3) with 0.200MHCI, calculate the pH at the equivalence point. The K of ammonia is 1.80 × 10 . Please show your work. b -5 1. For the titration of 30.00 mL of 0.120 M aqueous solution of ammonia (NH3) with 0.200 M HCI, calculate the pH at the equivalence point. The Kb of ammonia is 1.80 x10-5. Please show your work. 23 SA NH + HCI == сітлений Hy .ROM - 03 =
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