For the thermal cracking of ethane in a tubular reactor the following data were obtained for the reaction rate constant at difference reference temperatures:T (K) 975 998 1007 1027 1046 1062 1076 1083 1100 1110k(s-1) 0.15 0.273 0.333 0.595 0.923 1.492 2.138 2.718 4.137 4.665Based on these data find the activation energy and preexponential coefficient using method of linear regression. For the thermal cracking of ethane in a tubular reactor the following data wereobtained for the reaction rate constant at difference reference temperatures:1007 1027| 1046 1062 1076k (s') | 0.15 | 0.273 | 0.333 | 0.595 | 0.923 | 1.492 2.138 || 2.718 | 4.137 4.665T (K) | 9759981083 1100 | 1110Based on these data find the activation energy and preexponential coefficient usingmethod of linear regression.

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Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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For the thermal cracking of ethane in a tubular reactor the following data were obtained for the reaction rate constant at difference reference temperatures:

T (K) 975 998 1007 1027 1046 1062 1076 1083 1100 1110

k(s-1) 0.15 0.273 0.333 0.595 0.923 1.492 2.138 2.718 4.137 4.665
Based on these data find the activation energy and preexponential coefficient using method of linear regression.

For the thermal cracking of ethane in a tubular reactor the following data were
obtained for the reaction rate constant at difference reference temperatures:
1007 1027| 1046 1062 1076
k (s') | 0.15 | 0.273 | 0.333 | 0.595 | 0.923 | 1.492 2.138 || 2.718 | 4.137 4.665
T (K) | 975
998
1083 1100 | 1110
Based on these data find the activation energy and preexponential coefficient using
method of linear regression.

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