For the system in the diagram: 1. The line current at startup. Use this per-phase equivalent circuit: Apply Ohm's law, note that slip is equal to 1 at startup and the resulting current is complex. Show the current in polar form. 2. The starting torque. For each phase, Tstart = Pin/ധs , and the input power is the "line current squared times the equivalent rotor resistance given as 0.25/slip with slip = 1 at startup." 3. Find the full-load current with a star starter and the power factor. Use Ifl = VL/Zeq, VL from the above circuit, and Zeq must include the slip calculated in problem 4. Show the complex current in polar form 4. Determine the full-load torque. The suitable formula for the full-load torque is derived as: Tfl = (per phase x 3) Ifl2 x Req / (ധs x slip). Req is the sum of all the resistive impedances from the above circuit. Get the synchronous speed, and slip from problem 4.   Note: From Problem 4: Synchronous Speed Ns = 1800 rpm Slip s = 2.5%

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For the system in the diagram:

1. The line current at startup. Use this per-phase equivalent circuit:
Apply Ohm's law, note that slip is equal to 1 at startup and the resulting current is complex. Show the current in polar form.

2. The starting torque. For each phase, Tstart = Pin/ധs , and the input power is the "line current squared times the equivalent rotor resistance given as 0.25/slip with slip = 1 at startup."

3. Find the full-load current with a star starter and the power factor. Use Ifl = VL/Zeq, VL from the above circuit, and Zeq must include the slip calculated in problem 4. Show the complex current in polar form

4. Determine the full-load torque. The suitable formula for the full-load torque is derived as:

Tfl = (per phase x 3) Ifl2 x Req / (ധs x slip). Req is the sum of all the resistive impedances from the above circuit. Get the synchronous speed, and slip from problem 4.

 

Note: From Problem 4:

Synchronous Speed Ns = 1800 rpm

Slip s = 2.5%

The image shows an electrical circuit diagram with a power source and several resistive components. Here's a detailed transcription and explanation:

### Circuit Diagram Description

- **Voltage Source:**
  - It is labeled as \(\frac{480}{\sqrt{3}} \, V\).

- **Resistors:**
  - There are five resistors in the circuit:
    - A \(0.15 \, \Omega\) resistor is in series with the voltage source.
    - A \(0.9 \, \Omega\) resistor is connected after the \(0.15 \, \Omega\) resistor.
    - A \(1.3 \, \Omega\) resistor is in series with the other resistors, located on the right side of branch \(AB\).
    - A \(0.25/s \, \Omega\) resistor is on the far right side of the circuit.
    - A \(50 \, \Omega\) resistor is connected in parallel with a \(21 \, \Omega\) resistor between points \(A\) and \(B\).

### Circuit Configuration

- The circuit consists of a series-parallel configuration.
- The \(50 \, \Omega\) and \(21 \, \Omega\) resistors create a parallel branch between points \(A\) and \(B\).
- The combination of these parallel resistors is in series with the resistors on each side (\(0.15 \, \Omega\), \(0.9 \, \Omega\), \(1.3 \, \Omega\), and \(0.25/s \, \Omega\)).

This setup is typically used to analyze the total resistance in an electrical circuit and calculate various circuit parameters such as current and voltage distribution across different branches.
Transcribed Image Text:The image shows an electrical circuit diagram with a power source and several resistive components. Here's a detailed transcription and explanation: ### Circuit Diagram Description - **Voltage Source:** - It is labeled as \(\frac{480}{\sqrt{3}} \, V\). - **Resistors:** - There are five resistors in the circuit: - A \(0.15 \, \Omega\) resistor is in series with the voltage source. - A \(0.9 \, \Omega\) resistor is connected after the \(0.15 \, \Omega\) resistor. - A \(1.3 \, \Omega\) resistor is in series with the other resistors, located on the right side of branch \(AB\). - A \(0.25/s \, \Omega\) resistor is on the far right side of the circuit. - A \(50 \, \Omega\) resistor is connected in parallel with a \(21 \, \Omega\) resistor between points \(A\) and \(B\). ### Circuit Configuration - The circuit consists of a series-parallel configuration. - The \(50 \, \Omega\) and \(21 \, \Omega\) resistors create a parallel branch between points \(A\) and \(B\). - The combination of these parallel resistors is in series with the resistors on each side (\(0.15 \, \Omega\), \(0.9 \, \Omega\), \(1.3 \, \Omega\), and \(0.25/s \, \Omega\)). This setup is typically used to analyze the total resistance in an electrical circuit and calculate various circuit parameters such as current and voltage distribution across different branches.
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