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For the soil profile shown below, calculate the primary consolidation settlement due to 150 kPa net foundation loading (take w = 10 kN/m3). Assume the foundation loading is distributed at angle of 450 with depth at midpoints of clay layers 1 and 2, below the footing. 10 m X 10 m 150 Kpa CLAY 1 E G.W.T Y- 19 KN/m - 20 KN/m P = 80 Kpa , e, = 0.8 C.- 0. 15, C, - 0.05 CLAY 1 L- 20 KN/m P = 200 Kpa, e = 0.6 C.= 0.1 CLAY 2 E C, = 0.03 INCOMPRESSIBLE wg

For the soil profile shown below, calculate the primary consolidation settlement due to 150 kPa net foundation loading (take w = 10 kN/m3). Assume the foundation loading is distributed at angle of 450 with depth at midpoints of clay layers 1 and 2, below the footing. 10 m X 10 m 150 Kpa CLAY 1 E G.W.T Y- 19 KN/m - 20 KN/m P = 80 Kpa , e, = 0.8 C.- 0. 15, C, - 0.05 CLAY 1 L- 20 KN/m P = 200 Kpa, e = 0.6 C.= 0.1 CLAY 2 E C, = 0.03 INCOMPRESSIBLE wg

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Q - 6 (10 Marks) For the soil profile shown below, calculate the primary consolidation settlement due to 150 kPa net foundation loading (take w = 10 kN/m3). Assume the foundation loading is distributed at angle of 450 with depth at midpoints of clay layers 1 and 2, below the footing. 10 m X 10 m. 150 Kpa CLAY 1 G.W.T Y = 19 KN/m Y- 20 KN/m P = 80 Kpa , e, - 0.8 C = 0. 15, C, - 0.05 CLAY 1 Y= 20 KN/m P = 200 Kpa, e = 0.6 C. = 0.1 CLAY 2 C, = 0.03 INCOMPRESSIBLE
Transcribed Image Text:Q - 6 (10 Marks) For the soil profile shown below, calculate the primary consolidation settlement due to 150 kPa net foundation loading (take w = 10 kN/m3). Assume the foundation loading is distributed at angle of 450 with depth at midpoints of clay layers 1 and 2, below the footing. 10 m X 10 m. 150 Kpa CLAY 1 G.W.T Y = 19 KN/m Y- 20 KN/m P = 80 Kpa , e, - 0.8 C = 0. 15, C, - 0.05 CLAY 1 Y= 20 KN/m P = 200 Kpa, e = 0.6 C. = 0.1 CLAY 2 C, = 0.03 INCOMPRESSIBLE
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