For the shown vertical curve. Determine: 1-Stations & Elevations for PVC & PVI 2- STA & Elev for the highest point on the curve. PVC + 1.55% PVI -3.65% PVT 2+431.05 Elev@PVT= 236.62 m L=270 m
For the shown vertical curve. Determine: 1-Stations & Elevations for PVC & PVI 2- STA & Elev for the highest point on the curve. PVC + 1.55% PVI -3.65% PVT 2+431.05 Elev@PVT= 236.62 m L=270 m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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This question about Transportation Engineering

Transcribed Image Text:260
261
Design Crest Vertical Curve:
Design Criteria:
Stopping Sight Distance (S)
Stopping sight distance-
Length of crest vertical curve (L)-
CONEN 442 Transportation Engineering W2022
VPC
For h1 =1.08 m & h2 = 0.60 m,
then we can use the following:
CONEN 442 Transportation Engineering W2022
where:
L
S
A
Metric
When S is less than L
AS²
100/2h+√2h₂
When S is greater than L,
L=
L=2S-
Design Crest Vertical Curve:
-Stopping sight distorce-
L =
= length of vertical curve, m;
sight distance, m;
= algebraic difference in grades,
percent;
hheight of eye above roadway
surface, m;
h₂= height of object above
roadway surface, m
200(√₁+√₂)
A
-Length of crest vertical curve (L)
Metric
When S is less than L,
AS²
658
When S is greater than L,
L = 2S -
658
A
EIDessouk
Dessou

Transcribed Image Text:259
Vertical Curves: Geometric Characteristics
Example:
For the shown vertical curve. Determine:
1- Stations & Elevations for PVC & PVI
2- STA & Elev for the highest point on the curve.
CONEN 442 Transportation Engineering W2022
PVC
+ 1.55%
PVI
- 3.65%
PVT 2+431.05
Elev@PVT= 236.62 m
L=270 m
ElDessouki
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