For the shown figure below. Plot the pressure diagram and find the resultant force Fand its location under active conditions. q=2ksf 6n = 32° y = 110 pcf K, - 0.307 G.W.T 21 - 30° y= 125 pcf =K, = 0.333 = 10° y= 126 pcf K, = 0.704 c = 600 pcf 30ft = 0° Y = 120 pcf K, =1 c= 800 pcf = 20° y = 120 pcf 5t K, - 0.49 c = 400 pcf -무 - Use Rankine's Theory

For the shown figure below. Plot the pressure diagram and find the resultant force Fand its location under active conditions. q=2ksf 6n = 32° y = 110 pcf K, - 0.307 G.W.T 21 - 30° y= 125 pcf =K, = 0.333 = 10° y= 126 pcf K, = 0.704 c = 600 pcf 30ft = 0° Y = 120 pcf K, =1 c= 800 pcf = 20° y = 120 pcf 5t K, - 0.49 c = 400 pcf -무 - Use Rankine's Theory

Structural Analysis

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ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Pressure and Stress

Question

for the figure shown below plot the pressure diagram and find the resultant force F and its location under active condition:
Use Rankine's Theory

---
For the shown figure below. Plot the pressure diagram and find the resultant force Fand its location
under active conditions.
q=2ksf
6n = 32°
y = 110 pcf K, = 0.307
GW.T
2n - 30° Y = 125 pcf =K, = 0.333
$ = 10° y = 126 pcf
K, = 0.704
c= 600 pcf
30ft
+ = 0° Y= 120 pef
K, = 1
c= 800 pcf
20° y= 120 pcf
c = 400 pcf
=
K, = 0.49
Use Rankine's Theory

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