For the set of data given below MACHINE D PART NO UNIT COST 1293 P 300 P 457 P 457 Rs.500 1013 Rs 350 1013 Rs.600 1011 P 300 Rs.650 1013 P 104 Rs. 500 1221 P 104 Rs.650 1011 P 300 Rs.490 Construct a linear Primary dense index on MACHINE ID attribute which has duplic 1) values where each data block can hold 2 data items 2) Construct a linear Secondary dense index on Unit cost attribute where each data blo can hold 2 data items

For the set of data given below MACHINE D PART NO UNIT COST 1293 P 300 P 457 P 457 Rs.500 1013 Rs 350 1013 Rs.600 1011 P 300 Rs.650 1013 P 104 Rs. 500 1221 P 104 Rs.650 1011 P 300 Rs.490 Construct a linear Primary dense index on MACHINE ID attribute which has duplic 1) values where each data block can hold 2 data items 2) Construct a linear Secondary dense index on Unit cost attribute where each data blo can hold 2 data items

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

See similar textbooks

Related questions

Q: Suppose that we are using an extendable hash structure with buckets that can hold 3 records, and the…

A: The technique of converting any given key or set of characters into another quantity is known as…

Q: 6. Design a data structure that has the following properties: • Find median takes O(1) time •…

A: In this question we need to design a data structure which can perform given operations in given…

Q: Please written by computer source This question asks you to perform competitive analysis of…

A: The question is related to computer science, specifically in the area of algorithm analysis and…

Q: When is it better to use a dense index than a sparse index? Your answer has to be explained.

A: According to the information given:- WE have to define dense index is better than a sparse index…

Q: Explain the key stream generator (LFSR) given by the recurrence relation S+5 = (S + S+2 + Si43) mod…

A: Linear feedback shift register: A linear feedback shift register is a special type of recurrence…

Q: Problem 3: 50%] Implement using any programming language, preferably in Python, the NIST digital…

A: The NIST Digital Signature Algorithm (DSA) is a widely-used cryptographic algorithm for generating…

Q: 2. Which memory locations are assigned by the hashing function h(k) = k mod 101 to the records of…

A: % returns the remainder left over when one operand is divided by a second operand. a) 104578690 h(k)…

Q: Show using either definition or limit theorem that n^2+n sqrt(n) does not belong to O(n log n). Edit…

A: Given Information : Two function f1(n) = n2 + nsqrt(n) f2(n) = nlogn The task is to check…

Q: In elementwise multiplication A.*B each value in one matrix is paired up with a buddy value in the…

A: for first question correct answer is dot(A[1:],B[:1])

Q: (2) Consider the following fragment of a positional index with the format: word: document: ;…

A: The set of documents that satisfy the query Gates /2 Microsoft are {1, 3}Option 2 is…

Q: Algorithm to Locating p-Central Elements function p_central( G:group; p:prime ):element; (* Given a…

A: given data: function p_central( G:group; p:prime ):element; (* Given a group G of order p ms, where…

Q: write a recurrence relation describing the running time of algorithm modified merge sort(A, p,r)…

A: The task from the above given question is to explain about the recurrence relation by describing run…

Q: For the given allocation and max below, what is the need matrix? Allocation 3 + A 3 2 B S 2 C D 4 1…

A: Allocation Matrix: The allocation matrix, which is a two-dimensional matrix, shows how many of each…

Q: matrix of dimension m*n where each cell in the matrix can have values 0, 1 or 2 which has the…

Q: 5. Data Matrix Point X Y P1 4 P2 4 2 P3 6. P4 5 1. B. Determine the City Block Distance matrix and…

A: City block distance:

Question

100%

For the set of data given below
MACHINE ID
PART NO
UNIT COST
1293
P_300
Rs.500
1013
P_457
Rs.350
1013
P 457
Rs.600
1011
P_300
Rs.650
1013
P 104
Rs.500
1221
P_104
Rs.650
1011
P 300
Rs.490
Construct a linear Primary dense index on MACHINE_ID attribute which has duplica
values where each data block can hold 2 data items
2) Construct a linear Secondary dense index on Unit cost attribute where each data bloc
can hold 2 data items

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

Q3. Compute the cost of r JOINA=B s using the method of index loops with an index of height 2 on B of s. Do the computation for the clustering index case. Assume that r occupies 4,000 blocks with 20 tuples per block, s occupies 10,000 blocks with 5 tuples per block, and the amount of main memory available is 402 blocks. Assume that at most 5 tuples in s match each tuple in r.
HW9_3 The following data set represents the growth rate of bacteria k (per d) as a function of oxygen concentration c (mg/L) and can be modeled by the equation k = Kmax c? (Cs+ c²) c (mg/L) k (/day) 0.5 0.8 1.5 2.5 4.0 1.1 2.5 5.3 7.6 8.9 Linearize & solve for the linearized model coefficients using a MATLAB built-in function. Plot the straight line along with the linearized data. Next, determine the coefficients for the original model, and then create a second figure showing the original data points, and the model function. Place a title on each figure & label axes. Compute r' for both the linearized fit and the growth model fit and place it on the plots with the text command.
Write Algorithm for Ordered weighted aggregation.OWA(M,W)in: sequence of membership values M; sequence of weights Wout: aggregated result
python # Initialize a 6x6 matrix with all elements as 0 matrix = [[0 for _ in range(6)] for _ in range(6)] # Fill in the matrix for i in range(6): # Iterate over rows for j in range(6): # Iterate over columns if i > j: matrix[i][j] = 3*j - 4*i else: matrix[i][j] = 0 # Print the matrix for row in matrix: print(row)
Consider the following Python code: # 1.a first estimate model using NWS SE # dictionary with cov options # cov_opts = {'maxlags':24, # number of NW lags for SE # 'use_correction':True} # small sample correction # reg_fit = smf.ols("LeadReal ~ 1", data=df).fit(cov_type='HAC', # cov type # # 1.b first estimate model using reg_fit = smf.ols("LeadReal ~ 1", data=df).fit() cov_kwds=cov_opts) # 2. extract info from reg object reg_fit.params reg_fit.bse # extract only coeff # extract only SE reg_fit.summary() # print nice reg table with more info a. b. C. d. This code produces HAC-adjusted standard errors as is This code features a biased estimator The commented (#) part of this code specifies the options required for the HAC-adjusted standard errors All of the above
find the result of the following commands on matrix [A] Z=4509 8327 10 2 16 1)sum (diag(fliplr(A'))) 2)tril(fliplr(A')) 3)sum (diag(A)) 4) In the above matrix change all elements that are above 6 to 10.
write a C++ program to Given a matrix of dimension m*n where each cell in the matrix can have values 0, 1 or 2 whichhas the following meaning:0: Empty cell1: Cells have fresh oranges2: Cells have rotten orangesSo we have to determine what is the minimum time required so that all the oranges becomerotten. A rotten orange at index [i,j] can rot other fresh orange at indexes [i-1,j], [i+1,j], [i,j-1],[i,j+1] (up, down, left and right). If it is impossible to rot every orange then simply return -1.Examples:Input: arr[][C] = { {2, 1, 0, 2, 1},{1, 0, 1, 2, 1},{1, 0, 0, 2, 1}};Output:All oranges can become rotten in 2 time frames.Input: arr[][C] = { {2, 1, 0, 2, 1},Tahir Iqbal Department of Computer Sciences. BULC{0, 0, 1, 2, 1},{1, 0, 0, 2, 1}};Output:All oranges cannot be rotten.Below is algorithm.1) Create an empty Q.2) Find all rotten oranges and enqueue them to Q. Also enqueuea delimiter to indicate beginning of next time frame.3) While Q is not empty do following3.a) While delimiter in…
1. The performance of hash table O A Related to the method of handling conflicts, not the length of the table O B It has nothing to do with the method of handling conflicts, but with the length of the table OC It is related to the conflict handling method and table length OD It has nothing to do with conflict handling methods and table length 2 When using binary search, the linear list must be A Store in Sequential List B Store in linked List OC Store in Sequential List, and the list is ordered by keywords OD Store in linked List, and the list is ordered by keywords