Find the probability that a randomly selected person was a crew member, given that the person survived.Contingency table results:Rows: SurvivalColumns: ClassCell formatCount(Row percent)(Column percent)(Percent of total) CrewFirstSecondThirdTotalAlive212(29.82%)(23.95%)(9.63%)203(28.55%)(62.46%)(9.22%)118(16.6%)(41.4%)(5.36%)178(25.04%)(25.21%)(8.09%)711(100%)(32.3%)(32.3%)Dead673(45.17%)(76.05%)(30.58%)122(8.19%)(37.54%)(5.54%)167(11.21%)(58.6%)(7.59%)528(35.44%)(74.79%)(23.99%)1490(100%)(67.7%)(67.7%)Total885(40.21%)(100%)(40.21%)325(14.77%)(100%)(14.77%)285(12.95%)(100%)(12.95%)706(32.08%)(100%)(32.08%)2201(100%)(100%)(100%)

It is given that Total persons = 2201 Number of persons survived = 711 Number of crew persons…

Answered: Find the probability that a randomly…

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

1st Edition

ISBN:9781680331141

Author:HOUGHTON MIFFLIN HARCOURT

Publisher:HOUGHTON MIFFLIN HARCOURT

Chapter11: Data Analysis And Displays

Section: Chapter Questions

Problem 4CR

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Contingency table results:

Rows: Survival
Columns: Class

Cell format
Count (Row percent) (Column percent) (Percent of total)

	Crew	First	Second	Third	Total
Alive	212 (29.82%) (23.95%) (9.63%)	203 (28.55%) (62.46%) (9.22%)	118 (16.6%) (41.4%) (5.36%)	178 (25.04%) (25.21%) (8.09%)	711 (100%) (32.3%) (32.3%)
Dead	673 (45.17%) (76.05%) (30.58%)	122 (8.19%) (37.54%) (5.54%)	167 (11.21%) (58.6%) (7.59%)	528 (35.44%) (74.79%) (23.99%)	1490 (100%) (67.7%) (67.7%)
Total	885 (40.21%) (100%) (40.21%)	325 (14.77%) (100%) (14.77%)	285 (12.95%) (100%) (12.95%)	706 (32.08%) (100%) (32.08%)	2201 (100%) (100%) (100%)

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For the same chart above>>Find the probability that a randomly selected person was a crew member or did not survive.

I did p(A)+p(B) which gave me 1.08, rounded to two decimal places. Is that correct? I am not sure I understand the chapter explanation for two disjointed events.

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