For the reduction 2FeCl3 + SnCl2 =====→ 2 FeCl2 + SnCl4 in aqueous solution the following data were obtained at 25°C t(min) 3 7 11 40 Y 0.01434 0.02664 0.03612 0.04102 0.05058 Where y is the amount of FeCl3 reacted in moles per liter. The initial concentrations of SnCl3 and FeCl; were respectively, 0.03125, 0.0625 moles/L. Show that the reaction is third order (derive the rate law), and calculate the average specific rate constant.

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For the reduction 2FeCl3 + SnCl2 =====➔ 2 FeCl2 + SnCl4 in aqueous solution the following data were obtained at 25oC

              t(min)              1                      3                      7                      11                    40

                 Y              0.01434            0.02664             0.03612             0.04102           0.05058

 

Where y is the amount of FeCl3 reacted in moles per liter. The initial concentrations of SnCl3 and FeCl3 were respectively, 0.03125, 0.0625 moles/L. a.)Show that the reaction is third order (derive the rate law), and b.) calculate the average specific rate constant.

For the reduction 2FeCl3 + SnCl2 =====→ 2 FeCl2 + SnCl4 in aqueous solution the following data were
obtained at 25°C
t(min)
3
7
11
40
Y
0.01434
0.02664
0.03612
0.04102
0.05058
Where y is the amount of FeCl3 reacted in moles per liter. The initial concentrations of SnCl3 and FeCl; were
respectively, 0.03125, 0.0625 moles/L. Show that the reaction is third order (derive the rate law), and
calculate the average specific rate constant.
Transcribed Image Text:For the reduction 2FeCl3 + SnCl2 =====→ 2 FeCl2 + SnCl4 in aqueous solution the following data were obtained at 25°C t(min) 3 7 11 40 Y 0.01434 0.02664 0.03612 0.04102 0.05058 Where y is the amount of FeCl3 reacted in moles per liter. The initial concentrations of SnCl3 and FeCl; were respectively, 0.03125, 0.0625 moles/L. Show that the reaction is third order (derive the rate law), and calculate the average specific rate constant.
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