Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The reaction involves the following steps:
1. Treatment with excess NaNH₂
2. Addition of H₂O
**Reactants and Possible Products:**
The reactant is a molecule with the structure containing two bromine atoms (Br) on adjacent carbon atoms.
The possible products of the reaction are labeled as follows:
1. **Product I**: ```H3C-CH=CH-CH=CH2```
2. **Product II**: ```H3C-C≡C-CH3```
3. **Product III**: ```H3C-CH(NH2)-CH2(NH2)-CH3```
4. **Product IV**: ```H3C-CH2-C≡CH```
5. **Product V**: ```H3C-CH=CH-CH3```
**Answer Choices:**
- **A**: I
- **B**: II
- **C**: III
- **D**: IV
- **E**: V
**Analysis:**
The addition of excess sodium amide (NaNH₂) commonly performs elimination reactions, leading to the formation of alkynes. Following that, the addition of H₂O would not drastically change the formed alkyne structure.
- **Potential Major Product**:
The expected major product after both steps is likely **Product II (II)**,
which is **4-methyl-2-pentyne (H3C-C≡C-CH3)** considering typical elimination
reaction outcomes and stability.
**Correct Answer:**
- **B**: II](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec41627d-7715-46d4-accb-fe042454172c%2F1478c23d-ca5e-4f87-ac69-130ace85715f%2F5033gpy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Organic Chemistry Reaction: Identifying the Major Product
**Problem Statement:**
For the reaction shown below, select the expected major product.

The reaction involves the following steps:
1. Treatment with excess NaNH₂
2. Addition of H₂O
**Reactants and Possible Products:**
The reactant is a molecule with the structure containing two bromine atoms (Br) on adjacent carbon atoms.
The possible products of the reaction are labeled as follows:
1. **Product I**: ```H3C-CH=CH-CH=CH2```
2. **Product II**: ```H3C-C≡C-CH3```
3. **Product III**: ```H3C-CH(NH2)-CH2(NH2)-CH3```
4. **Product IV**: ```H3C-CH2-C≡CH```
5. **Product V**: ```H3C-CH=CH-CH3```
**Answer Choices:**
- **A**: I
- **B**: II
- **C**: III
- **D**: IV
- **E**: V
**Analysis:**
The addition of excess sodium amide (NaNH₂) commonly performs elimination reactions, leading to the formation of alkynes. Following that, the addition of H₂O would not drastically change the formed alkyne structure.
- **Potential Major Product**:
The expected major product after both steps is likely **Product II (II)**,
which is **4-methyl-2-pentyne (H3C-C≡C-CH3)** considering typical elimination
reaction outcomes and stability.
**Correct Answer:**
- **B**: II
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