For the reaction shown below, select the expected major product. Br 1. excess NaNH2 2. H20 Br NH2 C-CH2 NH2

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### Organic Chemistry Reaction: Identifying the Major Product

**Problem Statement:**
For the reaction shown below, select the expected major product.

![Chemical Reaction](image)

The reaction involves the following steps:
1. Treatment with excess NaNH₂
2. Addition of H₂O

**Reactants and Possible Products:**
The reactant is a molecule with the structure containing two bromine atoms (Br) on adjacent carbon atoms. 

The possible products of the reaction are labeled as follows:
1. **Product I**: ```H3C-CH=CH-CH=CH2```
2. **Product II**: ```H3C-C≡C-CH3```
3. **Product III**: ```H3C-CH(NH2)-CH2(NH2)-CH3```
4. **Product IV**: ```H3C-CH2-C≡CH```
5. **Product V**: ```H3C-CH=CH-CH3```

**Answer Choices:**
- **A**: I
- **B**: II
- **C**: III
- **D**: IV
- **E**: V

**Analysis:**
The addition of excess sodium amide (NaNH₂) commonly performs elimination reactions, leading to the formation of alkynes. Following that, the addition of H₂O would not drastically change the formed alkyne structure. 

- **Potential Major Product**:
  The expected major product after both steps is likely **Product II (II)**, 
  which is **4-methyl-2-pentyne (H3C-C≡C-CH3)** considering typical elimination 
  reaction outcomes and stability.

**Correct Answer:**
- **B**: II
Transcribed Image Text:### Organic Chemistry Reaction: Identifying the Major Product **Problem Statement:** For the reaction shown below, select the expected major product. ![Chemical Reaction](image) The reaction involves the following steps: 1. Treatment with excess NaNH₂ 2. Addition of H₂O **Reactants and Possible Products:** The reactant is a molecule with the structure containing two bromine atoms (Br) on adjacent carbon atoms. The possible products of the reaction are labeled as follows: 1. **Product I**: ```H3C-CH=CH-CH=CH2``` 2. **Product II**: ```H3C-C≡C-CH3``` 3. **Product III**: ```H3C-CH(NH2)-CH2(NH2)-CH3``` 4. **Product IV**: ```H3C-CH2-C≡CH``` 5. **Product V**: ```H3C-CH=CH-CH3``` **Answer Choices:** - **A**: I - **B**: II - **C**: III - **D**: IV - **E**: V **Analysis:** The addition of excess sodium amide (NaNH₂) commonly performs elimination reactions, leading to the formation of alkynes. Following that, the addition of H₂O would not drastically change the formed alkyne structure. - **Potential Major Product**: The expected major product after both steps is likely **Product II (II)**, which is **4-methyl-2-pentyne (H3C-C≡C-CH3)** considering typical elimination reaction outcomes and stability. **Correct Answer:** - **B**: II
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