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For the reaction bellow: CnH(2n+2) + a(O₂ +3.76 N₂) → nCO₂ + (n + 1)H₂0 +3.76a N₂ If the heat of combustion writing as: Qc = 618.49 n + 187.83 (KJ/mole of fuel) 25 And the mole fraction of CO₂ in products is Xco₂ = find: " 227 1. Type of fuel. 2. Heat of combustion 3. If n=3, find the mole fractions of CO2, H₂O and N₂

For the reaction bellow: CnH(2n+2) + a(O₂ +3.76 N₂) → nCO₂ + (n + 1)H₂0 +3.76a N₂ If the heat of combustion writing as: Qc = 618.49 n + 187.83 (KJ/mole of fuel) 25 And the mole fraction of CO₂ in products is Xco₂ = find: " 227 1. Type of fuel. 2. Heat of combustion 3. If n=3, find the mole fractions of CO2, H₂O and N₂

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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For the reaction bellow: CnH(2n+2) + a(02 + 3.76 N2) → nC02 + (n + 1)H20 + 3.76a N2 If the heat of combustion writing as: Qc = 618. 49 n + 187. 83 And the mole fraction of CO2 in products is xco, (KJ/mole of fuel) 25 find: 227 1. Type of fuel. 2. Heat of combustion 3. If n=3, find the mole fractions of CO2, H20 and N2
Transcribed Image Text:For the reaction bellow: CnH(2n+2) + a(02 + 3.76 N2) → nC02 + (n + 1)H20 + 3.76a N2 If the heat of combustion writing as: Qc = 618. 49 n + 187. 83 And the mole fraction of CO2 in products is xco, (KJ/mole of fuel) 25 find: 227 1. Type of fuel. 2. Heat of combustion 3. If n=3, find the mole fractions of CO2, H20 and N2
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