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For the problem, min 8x1 + 12x2 s.t. 4x1 + 3x2 ≥ 20, 3x1 + x2 ≥ 10, x1 ≥ 0, x2 ≥ 0, the solution for x₁ is [Enter your answers as numbers in the boxes] the solution for x2 is the price for the first constraint is and the price for the second constraint is

For the problem, min 8x1 + 12x2 s.t. 4x1 + 3x2 ≥ 20, 3x1 + x2 ≥ 10, x1 ≥ 0, x2 ≥ 0, the solution for x₁ is [Enter your answers as numbers in the boxes] the solution for x2 is the price for the first constraint is and the price for the second constraint is

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The problem, max 4x1 + 12x2 s.t. 6x1 + 4x2 < 16, 2x1 + 2x2 < 9, x1 2 0, x2 2 0, find an equilibrium where the nonnegativity constraints are treated as resource constraints and assigned prices. [The problem max3(x,)²+6(x,)² s.t. 2x,+x,s8, x,20, x,20 is solved at x,=0, x=8. Is there an equilibrium pricep for the 2x,+x,58 constraint? That is, is there a p20 such that 3(x,)²+6(x,)²-p(2x,+x,) is maximized at x,=0, x=8?] The solution for x1 is the solution for x2 is the price for the 6x1 + 4x2 < 16 constraint is the price for the 2x1 + 2x2 < 9 constraint is the price for the x1 20 constraint is and the price for the x2 > 0 constraint is [Enter your answers as numbers in the boxes]
Transcribed Image Text:The problem, max 4x1 + 12x2 s.t. 6x1 + 4x2 < 16, 2x1 + 2x2 < 9, x1 2 0, x2 2 0, find an equilibrium where the nonnegativity constraints are treated as resource constraints and assigned prices. [The problem max3(x,)²+6(x,)² s.t. 2x,+x,s8, x,20, x,20 is solved at x,=0, x=8. Is there an equilibrium pricep for the 2x,+x,58 constraint? That is, is there a p20 such that 3(x,)²+6(x,)²-p(2x,+x,) is maximized at x,=0, x=8?] The solution for x1 is the solution for x2 is the price for the 6x1 + 4x2 < 16 constraint is the price for the 2x1 + 2x2 < 9 constraint is the price for the x1 20 constraint is and the price for the x2 > 0 constraint is [Enter your answers as numbers in the boxes]
For the problem, min 8x1 + 12x2 s.t. 4x1 + 3x2 > 20, 3x1 + x2 > 10, x1 2 0, x2 2 0, the solution for x1 is the solution for x2 is the price for the first constraint is and the price for the second constraint is [Enter your answers as numbers in the boxes]
Transcribed Image Text:For the problem, min 8x1 + 12x2 s.t. 4x1 + 3x2 > 20, 3x1 + x2 > 10, x1 2 0, x2 2 0, the solution for x1 is the solution for x2 is the price for the first constraint is and the price for the second constraint is [Enter your answers as numbers in the boxes]
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