For the part circled in red, my question is why is it 3-(y^2 +1)

Q: 6^2(3)+4=8 explain why the answer to this equation is incorrect. Provide the correct answer.

A: Given, The equation is 6^2(3)+4=8.

Q: (3x+4)^1\2=2x-4

A: solve the equation.

Q: 2x x +6>

A:

Q: Y=8x^2+8x+12

A:

Q: 3. Subtract 2x² – 9x + 6 from Sr -3x +7 %3D

A:

Q: Find the term of (a-2b)^13 that has b^3 in it.

A:

Q: (3a^3)(−2a^−5)

A:

Q: 3x^2+y^2=28 3(x-1)^2+y^2=19

A:

Q: ((-2×z^5)/(z^2*p^2))^-3 simplify

A: Solution

Q: (8x^2+6x-20)/(4x-5)

A: Given  8x2+6x-204x-5

Q: so the answer is x^3 =8 because x=2 there 2^3=8

A: One example of an equation that satisfies all the given conditions is:   e^x - e^3 = 0   In this…

Q: what is y=-4(x+5)^2-16 in standard form

A:

Q: (x-4)^2=2x^2-9x-14

A: Formula:

Q: For 2x^2+5=-x what is the correct substitution for a,b,and c in general form of ax2+bx+c=0 ??

A:

Q: (11x^ - 90x + 16) / (x - 8)

A: