1. For the part below that consists of a semicircle on top of a rectangle, with r = 7 in andh =1 in, determine:a. Centroid and y [in]b. Area moment of inertia I [in*]2r2. Determine what static coefficient of friction µ, is needed so that the part will not slidedown the hill with an angle 0:= 33° and a weight W = 174 N.W3. Determine the longitudinal center of gravity of a composite round bar that is made ofaluminum and steel stacked on top of each other. The aluminum piece has a diameter of0.5 in, a length of 6 inches and a density Ya = 0.098 #/in³. The steel piece has a diameterof 0.25 in, a length of 4 inches and a density Ys =bottom of aluminum piece and draw clearly the bar with dimensions.%3D0.284 #/in. Note: provide answer from

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For the part below that consists of a semicircle on top of a rectangle, h =1 in, determine: a. Centroid and y (in] b. Area moment of inertia I [in*] %3D h 2r-

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Center of Gravity and Centroid

The term center of gravity indicates the position or location of a point about which the whole weight of a body or system is supposed to be concentrated, which means the whole weight of the body or system works through this point. It is closely related to mass distribution. For all positions of the body, the center of gravity would be a single point.

Question

1. For the part below that consists of a semicircle on top of a rectangle, with r = 7 in and
h =1 in, determine:
a. Centroid and y [in]
b. Area moment of inertia I [in*]
2r
2. Determine what static coefficient of friction µ, is needed so that the part will not slide
down the hill with an angle 0:
= 33° and a weight W = 174 N.
W
3. Determine the longitudinal center of gravity of a composite round bar that is made of
aluminum and steel stacked on top of each other. The aluminum piece has a diameter of
0.5 in, a length of 6 inches and a density Ya = 0.098 #/in³. The steel piece has a diameter
of 0.25 in, a length of 4 inches and a density Ys =
bottom of aluminum piece and draw clearly the bar with dimensions.
%3D
0.284 #/in. Note: provide answer from

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