For the Parabola (5-x) = 20 ( 9 - y ) %3D Find the following: The focus is = (5 6. The Vertex is (5 6. The equation of directrix is: y = The equation of axis of symmetry is: x = 5

Q: Find the vertex, focus and directrix of the parabola given by (x - 2)2 = 4(y + 1)..Then graph the…

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Q: solve for the focus of the parabola 8y = -x2 + 4x + 36

A: Solution:-     As we know,           The equation of a parabola in a vertex form is…

Q: Use the information provided to write the equation of each parabola. Vertex: (-1,9), Focus: (-3, 9)…

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Q: Find the Parabola with Focus (7,-2) and Directrix x=-9

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Q: Q1) Find an equation of the following parabola and sketch it where Vertex: (3,2) and Focus:(1,2)

A: Given the vertex 3,2 and the focus 1,2 of a parabola. We need to find the equation of the parabola…

Q: Find an equation of the parabola drawn below: 0 Select one: 2 X a. (x-2)² = 2 (y + 2) O b. (x + 2)2…

A: We can answer the question as below.

Q: Determine the coordinates of the vertex (label V) and focus (label F) and the EQUATION of the…

A: standard form of the parabola ( x - h )2 = -4a( y - k ) where vertex = ( h , k ) Focus = ( 0 , -a )…

Q: Find the focus, directrix, and axis of (y - 2)2 = -8(x + 3). Then graph the parabola to scale.

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Q: Graph the parabola (x + 4)2 = –12(y – 2). Label the focus, directrix, vertex, and at least one…

A: According to our policy at Bartleby, I can solve only 3 sub- parts.  Given an equation of a…

Q: Fine the equation of the hyperbola with the dock being (-4, 0) and (4, 0); asymptote the line y=-x

A: Given:foci(-4,0),(4,0)asymptotes:y=-x,y=x