For the normal probability plot shown below, the correlation between the random variable X and expected z-scores is 0.889. Determine whether the sample data (n= 15) could have come from a population that isnormally distributed.Click the icon to view the normal probability plot.Click here to view the table of critical values of the correlation coefficient.OA. The normal probability plot does not indicate that the sample data could have come from a population that is normally distributedOB. The normal probability plot indicates that the sample data could have come from a population that is normally distributed Normal Probability Plot12Expected z-Score10-12Normal Probability Plot- 106Print100 x8X10Done511214X

Given that The correlation between X and expected z score is 0.889n= 15 sample size

Answered: For the normal probability plot shown…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Q6- Assume the probability that a maple tree at age 5 grows less than 140 cm is equal to 0.2. If the height of maple trees at age 5 are estimated to be normally distributed with mean ? cm and variance 81 cm. find ?.
For the normal probability plot shown below, the correlation between the random variable X and expected z-scores is 0.889. Determine whether the sample data (n = 15) could have come from a population that is normally distributed Click the icon to view the normal probability plot. Click here to view the table of critical values of the correlation coefficient. OA. The normal probability plot indicates that the sample data could have come from a population that is normally distributed B. The normal probability plot does not indicate that the sample data could have come from a population that is normally distributed
Draw R digram also
Refer to the accompanying table, which describes results from groups of 8 births from 8 different sets of parents. The random variable x represents the number of girls among 8 children. Find the mean and standard deviation for the number of girls in 8 births. Click the icon to view the data table. The mean is u= girl(s). (Round to one decimal place as needed.) The standard deviation is o = e# girl(s). (Round to one decimal place as needed.) Table of numbers of girls and probabilities Number of Girls x 0 1 2 3 4 5 6 7 8 átv P(x) 0.004 0.034 0.117 0.218 0.278 0.217 0.102 0.027 0.003 D - X NiZ Next
Refer to the accompanying table, which describes results from groups of 8 births from 8 different sets of parents. The random variable x represents the number of girls among 8 children. Find the mean and standard deviation for the number of girls in 8 births. Click the icon to view the data table. The mean is u = girl(s). (Round to one decimal place as needed.) The standard deviation is o = girl(s). (Round to one decimal place as needed.)
A certain prescription medicine is supposed to contain an average of 250 parts per million (ppm) of a certain chemical. If the concentration is higher than this, the drug may cause harmful side effects; if it is lower, the drug may be ineffective. The manufacturer runs a check to see if the mean concentration in a large shipment conforms to the target level of 250 ppm or not. A simple random sample of 100 portions is tested, and the sample mean concentration is found to be 247 ppm. The sample concentration standard deviation is s = 12 ppm. What are the appropriate null and alternative hypotheses? Group of answer choices H 0: x̄ = 250 vs. H a: x̄ < 250 H 0: x̄ = 250 vs. H a: x̄ ≠ 250 H 0: x̄ = 250 vs. H a: x̄ > 250 H 0: μ = 250 vs. H a:μ < 250 H 0: μ = 250 vs. H a: μ ≠ 250 H 0: μ = 250 vs. H a: μ > 250
An analyst found that the average amount of money in bank accounts at his/her bank is $2,000 with a standard deviation of $150. What would be the variance?
The average number of pounds of red meat a person consumes each year is 196 with a standard deviation of 22 pounds (Source: American Dietetic Association). If a sample of 50 individuals is randomly selected, find the probability that the mean of the sample will be greater than 200 pounds. OA. 0.0985 OB. 0.9015 OC. 0.8815 O D. 0.7613 C
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Dan is doing research on organic farming for an agricultural foundation. He has collected data on the number of oranges harvested from individual trees in two different orchards. In each orchard, the number of oranges harvested from each of 57 trees was recorded. The histograms below show the distributions of the two data sets. The means and standard deviations for the data sets are also given. Orchard 1 Orchard 2 25 25 20- 20- 15+ 15- 10+ 10+ 5+ 5+ 199.5 219.5 239.5 259.5 279.5 299.5 319.5 339.5 359.5 199.5 219.5 239.5 259.5 279.5 299.5 319.5 339.5 359.5 Orchard 1 mean: 275.1 oranges Orchard 2 mean: 274.9 oranges Orchard 1 standard deviation: 23.2 oranges Orchard 2 standard deviation: 47.9 oranges Dan wants to use the Empirical Rule to make some approximations about both data sets. Unfortunately, it is appropriate to use the Empirical Rule on only one of them! Answer the parts below to help Dan with his approximations. (a) Identify the data set for which it is appropriate to use the…
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