For the NMO circuit below, assuming the NMOS has Vt=1V, A= 0 (no channel-length modulation), and 0.5xK'n(W/L) = 0.50 mA/ V2. From the DC circuit, we have: VDD 1mA RD C2 Rs C1 Ta RL in 10k 0.2k 4k vin Zout Zin ID= -1mA (negative), VGS= -VDs ID=1mA, VGS=VDS ID=1mA, Vps=VGS-RBlin ID=0.5mA, VGS= - Vps (negative)
For the NMO circuit below, assuming the NMOS has Vt=1V, A= 0 (no channel-length modulation), and 0.5xK'n(W/L) = 0.50 mA/ V2. From the DC circuit, we have: VDD 1mA RD C2 Rs C1 Ta RL in 10k 0.2k 4k vin Zout Zin ID= -1mA (negative), VGS= -VDs ID=1mA, VGS=VDS ID=1mA, Vps=VGS-RBlin ID=0.5mA, VGS= - Vps (negative)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![For the NMO circuit below, assuming the NMOS has Vt=1V, A= 0 (no channel-length modulation), and 0.5xK'n(W/L) = 0.50 mA/ V2. From the DC circuit, we have:
VDD
1mA
RB
C2
Rs
C1
lin
10k
lo
ww
0.2k
RL
Vo
4k
vin
Zout
Zin
ID= -1mA (negative), VGS= -VDS
ID=1mA, VGS=VDS
ID=1mA, VDs-vGS-RBlin
ID=0.5mA, VGS= - Vps (negative)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe959e4c6-72c1-4dbb-968b-d4cf9fadf2b0%2Fbfdcf25e-e910-4e72-a98d-ba184d257439%2Fqhymtt_processed.png&w=3840&q=75)
Transcribed Image Text:For the NMO circuit below, assuming the NMOS has Vt=1V, A= 0 (no channel-length modulation), and 0.5xK'n(W/L) = 0.50 mA/ V2. From the DC circuit, we have:
VDD
1mA
RB
C2
Rs
C1
lin
10k
lo
ww
0.2k
RL
Vo
4k
vin
Zout
Zin
ID= -1mA (negative), VGS= -VDS
ID=1mA, VGS=VDS
ID=1mA, VDs-vGS-RBlin
ID=0.5mA, VGS= - Vps (negative)
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