For the next iteration, immediately assign to x the previous value of xnew (x=1.35), solve for f(x) and f'(x) which results to f(1.35) = 1.023 and f'(1.35) = 25.968. Continue steps 3 and 4 until you reach 5 iterations as stated in the problem. Take note of the number of decimal places to be rounded off. Apply the rules I have given you from the previous meeting. Completely fill out the table below. Table for Newton Raphson Method fx -7.000 1.023 X 1.000 1.350 f'x 20.000 25.968 xnew 1.350 fxnew 1.023
For the next iteration, immediately assign to x the previous value of xnew (x=1.35), solve for f(x) and f'(x) which results to f(1.35) = 1.023 and f'(1.35) = 25.968. Continue steps 3 and 4 until you reach 5 iterations as stated in the problem. Take note of the number of decimal places to be rounded off. Apply the rules I have given you from the previous meeting. Completely fill out the table below. Table for Newton Raphson Method fx -7.000 1.023 X 1.000 1.350 f'x 20.000 25.968 xnew 1.350 fxnew 1.023
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Newton Raphson Method
Iterative Formula:
Xnew = X – [f(x) / f’(x)]
f(x) = x3 + 5x2 + 7x – 20
Use initial value of (1). Stop if you reach 5 iterations.
COMPLETE THIS TABLE PLEASE

Transcribed Image Text:For the next iteration, immediately assign to x the previous value of xnew (x=1.35), solve for f(x) and
f'(x) which results to f(1.35) = 1.023 and f'(1.35) = 25.968. Continue steps 3 and 4 until you reach 5
iterations as stated in the problem. Take note of the number of decimal places to be rounded off. Apply
the rules I have given you from the previous meeting. Completely fill out the table below.
Table for Newton Raphson Method
fx
-7.000
1.023
X
1.000
1.350
f'x
20.000
25.968
xnew
1.350
fxnew
1.023
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