For the molecular compound silicon dioxide, what would you multiply "molecules of SiO," by to get the units "grams of SiO,"? molecules SiO2 = g SiO2

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Educational Content on Unit Conversion for Silicon Dioxide**

To convert from "molecules of silicon dioxide (SiO₂)" to "grams of SiO₂", you will need to consider the following conversion factors:

1. **Avogadro's Number**: This is used to convert molecules to moles. 
   - \( \text{1 mole of SiO}_2 = 6.022 \times 10^{23} \text{ molecules of SiO}_2 \).

2. **Molar Mass of SiO₂**: This is used to convert moles to grams.
   - The molar mass is the sum of atomic masses of silicon (Si) and oxygen (O), calculated as follows:
      - Silicon = 28.09 g/mol
      - Oxygen (O₂) = 2 × 16.00 = 32.00 g/mol
      - Total molar mass of SiO₂ = 28.09 + 32.00 = 60.09 g/mol

Here is the structured formula for the conversion:

\[ 
\text{molecules SiO}_2 \times \left( \frac{1 \text{ mole SiO}_2}{6.022 \times 10^{23} \text{ molecules}} \right) \times \left( \frac{60.09 \text{ g SiO}_2}{1 \text{ mole SiO}_2} \right) = \text{grams SiO}_2 
\]
Transcribed Image Text:**Educational Content on Unit Conversion for Silicon Dioxide** To convert from "molecules of silicon dioxide (SiO₂)" to "grams of SiO₂", you will need to consider the following conversion factors: 1. **Avogadro's Number**: This is used to convert molecules to moles. - \( \text{1 mole of SiO}_2 = 6.022 \times 10^{23} \text{ molecules of SiO}_2 \). 2. **Molar Mass of SiO₂**: This is used to convert moles to grams. - The molar mass is the sum of atomic masses of silicon (Si) and oxygen (O), calculated as follows: - Silicon = 28.09 g/mol - Oxygen (O₂) = 2 × 16.00 = 32.00 g/mol - Total molar mass of SiO₂ = 28.09 + 32.00 = 60.09 g/mol Here is the structured formula for the conversion: \[ \text{molecules SiO}_2 \times \left( \frac{1 \text{ mole SiO}_2}{6.022 \times 10^{23} \text{ molecules}} \right) \times \left( \frac{60.09 \text{ g SiO}_2}{1 \text{ mole SiO}_2} \right) = \text{grams SiO}_2 \]
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