For the mechanical translation system below, find the transfer function O1/T and02/T. Use the following values.K= 2+cD1 = 1J1 = 3+aJ2 = 2+bD2 = 5where a2b= 5C =oblems.T(t) 0(1)02(1)D1KD2

Answered: Image /qna-images/answer/3d49b64c-2053-4c5f-8003-a11f5551b0e4.jpg

For the mechanical translation system below, find the transfer function 01/T and 02/T. Use the following values. K= 2+c D1 = 1 J1 = 3+a J2 = 2+b 2 5 D2 = 5 where a = b = blems. T(t) 0(1) 02(1) J2 K D2

For the mechanical translation system below, find the transfer function 01/T and 02/T. Use the following values. K= 2+c D1 = 1 J1 = 3+a J2 = 2+b 2 5 D2 = 5 where a = b = blems. T(t) 0(1) 02(1) J2 K D2

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

200 OOOD O Subject Date: Q1/Find the domain P the function 2. Y3DIn(2x+X-6-6)
Consider the system shown in the figure below. Assume that when z is zero, that the spring is at its unstretched length. That is, the restoring force in the spring only develops when z, (the figure is a little misleading here). Note that z, is defined as positive to the left and zg is defined as positive downwards. Syntax notes: when entering your responses, use x[1] for z1and x2] for z2. m[1] for m1. m[2] for mg, and g for gravity. Use T for the tension in the rope. You can use the loupimagnifying glass to check that what you entered is what you intended. Kinematics The change in z is related to the change in zgsince they are part of the same string. What is the kinematic relationship between the two of them? 21- -2x(2] Kinetic Energy Write the total system kinetic energy. (ie write it in terms of both z1and zgand their velocities). Use diffio(1]t).) for ż and diffx(2]t).1) for ż KE = (12)m[1]*(difix[1]{t),f)^2+(1/2}*m[2]*(diff(x{2]{t),f)^2 Now use your kinematic relationship to write…
3. Write enough equations to create an expression for Vx. You may use node voltages here. ли ли R4 <+ Vx (+T R1 V1 ли R3 ли R2 + Vx
For the mechanical translation system below, find the transfer function X2/F and X1/F. Use the following values. K =1 fv = 1 M, = 4+a K2= 1/2 fv2 = 3+b M2 = 5 K3 = 1+c fv3 = 3/2 where a = 3rd digit of your student number %3D b = 5th digit of your student number %3D c = 7th digit of your student number For reference, the 1st digit of your student number is the leftmost number in your student number. Indicate your student number when solving problems.
where: a = 0 b = 7 c = 5
Page 8/5 Q4: (M4) LE Velocity: V [km/hr] Wavelength: L [m] M k y(t) Model Height: H [m] The figure above shows a model of a person riding a unicycle that contains a spring under its seat. The spring constant is k = 10,600 N/m. Assume that damping is minimal, the wheel of the unicycle has no mass and is not a spring, the unicyle always stays perfectly upright, and the person is represented by a rigid mass M = kg. a) When the unicycle is being ridden at speed V = 10 km/hr over the sinusoidal bumpy terrain shown above, with bump spacing L=0.6 m and bump height H 0.05 m, what will be the steady-state peak-to-peak amplitude of the motion y(t) [m] of the person riding the unicycle? b) Recalculate the steady-state peak-to-peak amplitude of the motion for 2.5, 5, and 20 km/hr. Will the rider have difficulty reaching speeds above 5 km/hr?
Help with a and b please
Q2/ For the system shown below, use Newton's method to find the system matrix [M],and [K]
Please answer in typing format
A crane hoisting system has the following transfer function. 1 s4 +5s3+s² + 7s+ 11 +s²+7s+ Identify the correct state-space form of the crane hoisting system from the list given below: 100T O a. 0 0 x = 0 -11 O b. x = = -5 1000 00 1 0 x + 01 1 5 1000 1 0700 0070 -1 -7 [−11 1 u; y = [1000]x x + u; y = [1_0_0 0]x 1111 ○ c. 0 1 0 0 0 0 1 0 x = + 0 0 0 1 -11 -7 -1 -5] O d. None of the above u; y = [1 0 0 0]x 2512220 12
Find the transfer function 04(s)/T(s). T(t) 04(1) 26 N-m-s/rad D4 = 3 J4 = 6 N1 = 26 N4= 120 Jj = 2 Dj = 1 N2 = 110 J2 = 1 D2=2 3 kg-m? N3 = 23 J3 = 1 D3 = 3
1