For the mechanical system shown, a- Find the equivalent mass, equivalent spring stiffness and equivalent damping coefficient when x (the displacement of the 2 kg block) is used as the generalized coordinate. b- Derive the equation of motion of the system in terms of equivalent system parameters (equivalent mass, equivalent spring stiffness and equivalent damping coefficient). 3000 N/m مد ادم 2 kg In /=0,04 kg-m r = 10 cm 200 1000 N.s/m N/m 1 kg 400 N.s/m
For the mechanical system shown, a- Find the equivalent mass, equivalent spring stiffness and equivalent damping coefficient when x (the displacement of the 2 kg block) is used as the generalized coordinate. b- Derive the equation of motion of the system in terms of equivalent system parameters (equivalent mass, equivalent spring stiffness and equivalent damping coefficient). 3000 N/m مد ادم 2 kg In /=0,04 kg-m r = 10 cm 200 1000 N.s/m N/m 1 kg 400 N.s/m
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![For the mechanical system shown,
a- Find the equivalent mass, equivalent
spring stiffness and equivalent damping
coefficient when x (the displacement of
the 2 kg block) is used as the generalized
coordinate.
b- Derive the equation of motion of the
system in terms of equivalent system
parameters (equivalent mass, equivalent
spring stiffness and equivalent damping
coefficient).
3000
N/m
2 kg
200
N.s/m
/=0.04 kg-m²
r = 10 cm
1000
N/m
1 kg
I'
400
N.s/m
ial](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcd97e35c-e999-4fc8-9388-4a2d136d4096%2F7d066a93-8ee0-49b8-96ff-4435fc20ea0e%2Fc67nbku_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the mechanical system shown,
a- Find the equivalent mass, equivalent
spring stiffness and equivalent damping
coefficient when x (the displacement of
the 2 kg block) is used as the generalized
coordinate.
b- Derive the equation of motion of the
system in terms of equivalent system
parameters (equivalent mass, equivalent
spring stiffness and equivalent damping
coefficient).
3000
N/m
2 kg
200
N.s/m
/=0.04 kg-m²
r = 10 cm
1000
N/m
1 kg
I'
400
N.s/m
ial
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