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For the mass spring damper system shown in the figure, assume that m = 0.25 kg, k= 2500 N/m, and c = 10 N.s/m. The values of force measured at 0.05-second intervals in one cycle are given below. time 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 F(t) 12 14 44 19 33 34 12 22 time 0.45 0.50 0.55 0.60 0.65 0.70 0.75 0.80 0.85 Force 32 11 18 25 30 49 40 35 21 time 0.90 0.95 F(t) 11 k +x F(t) 3- If we excite the system with initial displacement and velocity as 5 mm and 0.2 m/s respectively, plot the response of the free vibration system.

For the mass spring damper system shown in the figure, assume that m = 0.25 kg, k= 2500 N/m, and c = 10 N.s/m. The values of force measured at 0.05-second intervals in one cycle are given below. time 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 F(t) 12 14 44 19 33 34 12 22 time 0.45 0.50 0.55 0.60 0.65 0.70 0.75 0.80 0.85 Force 32 11 18 25 30 49 40 35 21 time 0.90 0.95 F(t) 11 k +x F(t) 3- If we excite the system with initial displacement and velocity as 5 mm and 0.2 m/s respectively, plot the response of the free vibration system.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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For the mass spring damper system shown in the figure, assume that m = 0.25 kg, k= 2500 N/m, and c = 10 N.s/m. The values of force measured at 0.05-second intervals in one cycle are given below. time 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 F(t) 12 14 44 19 33 34 12 22 time 0.45 0.50 0.55 0.60 0.65 0.70 0.75 0.80 0.85 Force 32 11 18 25 30 49 40 35 21 time 0.90 0.95 F(t) 11 k m +x F(t) 3- If we excite the system with initial displacement and velocity as 5 mm and 0.2 m/s respectively, plot the response of the free vibration system. 5- Find the steady state solution (only particular solution) for the forced vibration system. Take number of terms in your Fourier series terms from this range [ 30 – 55]. 6- Plot the force in the table, and the Fourier series expansion of the force (same graph). 7- Plot the steady state solution. 8- Find the total solution for the forced system with the initial conditions given in part 3. 9- Plot the total solution found in part 8.
Transcribed Image Text:For the mass spring damper system shown in the figure, assume that m = 0.25 kg, k= 2500 N/m, and c = 10 N.s/m. The values of force measured at 0.05-second intervals in one cycle are given below. time 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 F(t) 12 14 44 19 33 34 12 22 time 0.45 0.50 0.55 0.60 0.65 0.70 0.75 0.80 0.85 Force 32 11 18 25 30 49 40 35 21 time 0.90 0.95 F(t) 11 k m +x F(t) 3- If we excite the system with initial displacement and velocity as 5 mm and 0.2 m/s respectively, plot the response of the free vibration system. 5- Find the steady state solution (only particular solution) for the forced vibration system. Take number of terms in your Fourier series terms from this range [ 30 – 55]. 6- Plot the force in the table, and the Fourier series expansion of the force (same graph). 7- Plot the steady state solution. 8- Find the total solution for the forced system with the initial conditions given in part 3. 9- Plot the total solution found in part 8.
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