For the linear differential equation y' + 6xy = x³e' integrating factor is: -6x2 2 the r(x) = help (formulas) After multiplying both sides by the integrating factor and "unapplying" the product rule we get the new differential equation: d dx [0] = help (formulas) Integrating both sides we get the algebraic equation = + C help (formulas) Solving for y, the general solution to the differential equation is y = ☐ help (formulas) Note: Use C as the constant. Book: Section 1.4 of Notes on Diffy Qs
For the linear differential equation y' + 6xy = x³e' integrating factor is: -6x2 2 the r(x) = help (formulas) After multiplying both sides by the integrating factor and "unapplying" the product rule we get the new differential equation: d dx [0] = help (formulas) Integrating both sides we get the algebraic equation = + C help (formulas) Solving for y, the general solution to the differential equation is y = ☐ help (formulas) Note: Use C as the constant. Book: Section 1.4 of Notes on Diffy Qs
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![For the linear differential equation y' + 6xy = x³e'
integrating factor is:
-6x2
2 the
r(x)
=
help (formulas)
After multiplying both sides by the integrating factor and
"unapplying" the product rule we get the new differential
equation:
d
dx
[0] = help (formulas)
Integrating both sides we get the algebraic equation
=
+ C
help (formulas)
Solving for y, the general solution to the differential equation is
y = ☐ help (formulas)
Note: Use C as the constant.
Book: Section 1.4 of Notes on Diffy Qs](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff9a2dab3-72cf-4044-ac86-05d83f420c4a%2Ff0519a78-c550-482d-8b33-e7e2fd6e36c7%2Fwl7qca_processed.png&w=3840&q=75)
Transcribed Image Text:For the linear differential equation y' + 6xy = x³e'
integrating factor is:
-6x2
2 the
r(x)
=
help (formulas)
After multiplying both sides by the integrating factor and
"unapplying" the product rule we get the new differential
equation:
d
dx
[0] = help (formulas)
Integrating both sides we get the algebraic equation
=
+ C
help (formulas)
Solving for y, the general solution to the differential equation is
y = ☐ help (formulas)
Note: Use C as the constant.
Book: Section 1.4 of Notes on Diffy Qs
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