For the linear differential equation y' + 6xy = x³e' integrating factor is: -6x2 2 the r(x) = help (formulas) After multiplying both sides by the integrating factor and "unapplying" the product rule we get the new differential equation: d dx [0] = help (formulas) Integrating both sides we get the algebraic equation = + C help (formulas) Solving for y, the general solution to the differential equation is y = ☐ help (formulas) Note: Use C as the constant. Book: Section 1.4 of Notes on Diffy Qs