For the initisl value problem z"+4z' +13z = t, z(0) = -1,2(0) = 1, the Laplace trensform X(s) of the solution z(t) is (-8 - +5) s+3 3²+4s+13 1 s2+4s (-s 32(s²+4s+13) O 2. seçenek 3. seçenek + 32(8²+48+13) (-8 – 3 – ! + ) 3²+4s+13 52+4s O 4. seçenek 1. seçenek
For the initisl value problem z"+4z' +13z = t, z(0) = -1,2(0) = 1, the Laplace trensform X(s) of the solution z(t) is (-8 - +5) s+3 3²+4s+13 1 s2+4s (-s 32(s²+4s+13) O 2. seçenek 3. seçenek + 32(8²+48+13) (-8 – 3 – ! + ) 3²+4s+13 52+4s O 4. seçenek 1. seçenek
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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can you solve according to tables, please ?
Transcribed Image Text:For the initial value problem z"+4x' +13x = t, (0) = -1, 2'(0) = 1, the Laplace transform
X(s) of the solution z(t) is
Laplace Transform table
2
n!
t",n = 1, 2, 3, ...
n+1
s+3
82+4s+13
1
1
1
s2+4s
s2(s²+4s+13)
eat
S - a
n!
*eat, n = 1,2,3,...
(s -
a)2+1
a
sin at
2 + a?
2. seçenek
3. seçenek
a
ele sin at
(s - k)? + a?
(-s - 3 -!+)
1
s2 +4s+13
s2(s²+4s+13)
52+4s
4. seçenek
1. seçenek
Transcribed Image Text:Laplace Transforms
Laplace Transfor ms
F(s) = L{f(t)}
2 as
(g2 + a?)2
F(s) = L{f(t)}
f(t)
f(t)
Cif(t) + Cg(t)
CF(s) + CG(s)
tsin at
F(s - k)
1
cos at
g2 + a?
s - k
f(kt)
k
cosat
dF(s)
(s – k)² + a²
tf(t)
ds
g2 - a?
t cos at
d"F(s)
(-1)"-
ds"
(s2 + a² )²
a
sinh at
2 - a?
F(s)ds
coshat
s2 - at
F(s)
u(t - to)
1
u(t – to)f(t - o)
e-F(s)
1
8(t – to)
T(a + 1)
1
go, a > - 1
At), periodic of period p
e-"f(t)dt
ga+1
1 - e-ps
-1/2
f'(t)
sF(s) - K0)
V
sF(s) – sf(0) - f(0)
s"F(s) – s*-f0) -
f" (t)
1
F(s)G(s)
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