For the hypothesis test Ho : u the P-value for the test statistic to = -1.84. = 10 and H1 : u < 10, having variance unknown and sample size n = 12, finc A) .05 < p-value < .01 (B) 0 < p-value < .005 (C) .01 < p-value < .025 (D) .025 < p-value < .05 E) .05 < p-value < .1

For the hypothesis test Ho : u the P-value for the test statistic to = -1.84. = 10 and H1 : u < 10, having variance unknown and sample size n = 12, finc A) .05 < p-value < .01 (B) 0 < p-value < .005 (C) .01 < p-value < .025 (D) .025 < p-value < .05 E) .05 < p-value < .1

Name: = For the hypothesis test Ho : uthe P-value for the test statistic to
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: = For the hypothesis test Ho : uthe P-value for the test statistic to = -1.84.= 10 and H1 : u < 10, having variance unknown and sample size n = 12, findA).05 < p-value < .01(B) 0 < p-value < .005 (C) .01 < p-value < .025 (D) .025 < p-value < .05E) .

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

What is the value of the test statistic for a test with a null hypothesis that mu = 360, Xbar = 350, the sample standard deviation = 20 and n = 49?
The sample mean and standard deviation from a random sample of 32 observations from a normal population were computed asx =25 and s = 10. Calculate the t statistic of the test required to determine whether there is enough evidence to infer at the 8% significance level that the population mean is greater than 22.Test Statistic =
10. A study was conducted to identify if there is a significant difference with two brands of shampoo. Random sample A of 25 sheets of shampoo with a mean content of 237 grams and standard deviation of 8.56 grams. Another sample B of 20 sheets pf shampoo showed a mean content of 240 grams and standard deviation of 9.75 grams. Using 0.05 level of significance, conduct hypothesis testing assuming that variances are equal.
In a left-tailed hypothesis for a population mean where the population standard deviation is unknown, the test statistic for a random sample size 18 was calculated to be -4.0545. Determine the P-value for the test. X
A two-sided test of hypothesis assumes that a normally distributed random variable X with mean of 102.83 and standard deviation of 12.23 with alpha - 5% for a sample of size 4. If the real mean is 115 compute the power of the test.
Suppose you sample six people on their number of visits to Chick-fil-A in a month given by variable Y. Y = 3,6,7,10,15,19 (A) What is the mean of Y? Standard Deviation of Y?(B) What is the Standard Error of Y?(C) Construct 90% and 95% Confidence Intervals for Y.
A random sample of 100 private companies locating in Ankara was asked to rate on a scale from 1 (not important) to 5 (extremely important) for having the practical knowledge of statistics as a good job candidate. The sample mean rating was 4.7. a)Test at the 5% significance level the null hypothesis that the population mean rating is less than or equal to 4.5 against the alternative that it is greater than 4.5. Population variance is known as 0.6. b)Compute p-value and explain what the calculated p-value means.
mean(rsession$Years.of.secondary.schooling) [1] 4.255708 sd(rsession$Years.of.secondary.schooling) [1] 1.226018 Using the statistics calculated above, construct a 95% confidence interval for the mean number of years of secondary education for employed individuals in this country and briefly interpret this interval. Sample size = 219
Question is attached
part 2 marked as wrong result 1.2828) (a) X¯�¯ ~N(21.7000,1.2828) also part 2 questions are attached
What is the value of the test statistic for a test with a null hypothesis that mu = 83, Xbar = 85, the sample standard deviation = 2 and n = 49?
You are performing a two-tailed t-test with a sample size of 19If α=0.05, and your test statistic is t=1.69, do you (pick an option): Fail to Reject Null Hypothesis Reject Null Hypothesis