For the given series-shunt feedback circuit, Voc = 10 VB = 120 VBE(on)= 0.7 V Vcc VA= 0 RỊ = 400 k2 R2 = 75 k2 Rci = 8.8 k2 REI = 0.5 k2 Rc2 = 13 k2 RE2 = 3.6 k2 RF = 10 k2 Ce Rir Re Re RE3 = 1.4 K Cc. CE, CF 00 Q1. Q2. Q3 parameters gml =32.81 mA/V rl =3.66 K gm2 =19.12 mA/V 12 =6.28 K gm3 =78.08 mA/V 133 =1.54 RE H RE K a) Determine the closed loop voltage gain ArFvo'vi. b) Determine the input resistance Rit. c) Determine the output resistance Rof.

For the given series-shunt feedback circuit, Voc = 10 VB = 120 VBE(on)= 0.7 V Vcc VA= 0 RỊ = 400 k2 R2 = 75 k2 Rci = 8.8 k2 REI = 0.5 k2 Rc2 = 13 k2 RE2 = 3.6 k2 RF = 10 k2 Ce Rir Re Re RE3 = 1.4 K Cc. CE, CF 00 Q1. Q2. Q3 parameters gml =32.81 mA/V rl =3.66 K gm2 =19.12 mA/V 12 =6.28 K gm3 =78.08 mA/V 133 =1.54 RE H RE K a) Determine the closed loop voltage gain ArFvo'vi. b) Determine the input resistance Rit. c) Determine the output resistance Rof.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

020/2021 Q5: A linear feedback control system has the block diagram shown in figure 1. Using block diagram reduction rules, obtain the closed-loop transfer function C(s)/R(s). Hz R(s) G2 G3 C(s) H G4
= 5v1 – 2v2. Design the operational amplifier circuit so that vout = Operational amplifier circuit v1 20 k2 Vout v2
To convert a given block diagram R G/2 2H Into a unity feedback system R G₁ C G₁ should be-
If open-loop gain is divided by two, then gain crossover frequency will a. Becomes half b. not affected c. Gets doubled O d. Becomes one-fourth
Determine the phase margin (PM) of a unity gain feedback control system given the following open loop transfer function. G(s) = 1.15/(s + 1) a. 150⁰ O b. 0⁰ OC 60° Od. 180° O e. 30⁰ O 1.90⁰ O g. 1200 Clear my choice
Problem # 8 The scope sclickable &draable. More bere Each figure to the left shows two systems, an upper unity feedback gain and lower system which has an adjustable feedback gain. Both systems in each case (three cases) have a forward gain, Gain1, set always to 5 which is constant. Tme domaia plet Tme.demain.alot Sirpi Ietrgret ti Integrat 8. The feedback gain, Gain3, is varied from =8 to a value of C, which is 1.8. The upper response is in green and the pink response is for the lower system. As the feedback gain is decreased, what happens to the steady state error: T The scope is elikkatle&draggable. More here Time demain plet Intrgrat Cal Sempel A. IT INCREASES B. IT DECREASES Ca latrgrat Seepel c. IT IS THE SAME AS WE ARE NOT LOOKING AT THE STEADY STATE RESPONSE D. THESE FIGURES ARE ONLY SHOWING THE TRANSIENT RESPONSE Cala i h L N Lie Te Transfer Function Bode plot OrvOf Time Domain Scope Ovo Dewnear The scope s clickable & draatle. More here Time domain plot Call Iiegret Sepel…
Pls help thank you i'll rate
Determine the feedback voltage value in a negative feedback amplifier with A=100, ß =0.03, and input signal voltage = 40mv.
consider a sinusoid input with a peak amplitude of 2 mV. If the amplification gain A1 = 500 and k-0.125, the error (E) and the amplitude of the output waveform Vout of the feedback network are: R2 (a) Select one: O a. none of these O b. E=0.031m and Vout= 15.75mV O c. E= 127m and Vout= 15.75 O d. E=127m and Vout= 1V
Q) What is the type of negative feedback in the given circuit * Vc Rc Rg RE O Voltage shunt feedback Current series feedback O Current shunt feedback O Voltage series feedback
A current series circuit is also a A.transconductance amplifier B.transcurrent amplifier C.transvoltage amplifier D.current amplifier E.voltage amplifier F.transresistance amplifier
analyze the output voltage of inverting amplifier if input voltage is 20v input resistance is 60 ohm and feedback resistance is240 ohm a=-80v b=-60v c=-90v d=-75v