For the function g whose graph is shown, find a number a that satisfies the given description. The x y-coordinate plane is given. The function enters the window in the third quadrant, goes up and right becoming more steep, crosses the y-axis at approximately y = −0.5, crosses the x-axis at approximately x = 0.5, goes up and right becoming less steep, and stops at the approximate open point (2, 2.75). The function starts again at the approximate open point (2, 1.75), goes down and right becoming less steep, and stops at the approximate open point (4, 0.5). The functions starts again at the approximate closed point (4, 2.25), goes down and right becoming more steep, passes through the approximate open point (5, 1.75), crosses the x-axis at approximately x = 6.25, and exits the window in the fourth quadrant. (a) lim x→a g(x)  does not exist but g(a) is defined. a =   (b) lim x→a g(x)  exists but g(a) is not defined. a =   (c) lim x→a− g(x)  and  lim x→a+ g(x)  both exist but  lim x→a g(x)  does not exist. smaller valuea= larger valuea=  (d) lim x→a+ g(x) = g(a)  but  lim x→a− g(x) ≠ g(a). a =

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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For the function g whose graph is shown, find a number a that satisfies the given description.
The x y-coordinate plane is given.
  • The function enters the window in the third quadrant, goes up and right becoming more steep, crosses the y-axis at approximately y = −0.5, crosses the x-axis at approximately x = 0.5, goes up and right becoming less steep, and stops at the approximate open point (2, 2.75).
  • The function starts again at the approximate open point (2, 1.75), goes down and right becoming less steep, and stops at the approximate open point (4, 0.5).
  • The functions starts again at the approximate closed point (4, 2.25), goes down and right becoming more steep, passes through the approximate open point (5, 1.75), crosses the x-axis at approximately x = 6.25, and exits the window in the fourth quadrant.
(a)
lim x→a g(x)
 does not exist but g(a) is defined.
a =  
(b)
lim x→a g(x)
 exists but g(a) is not defined.
a =  
(c)
lim x→a g(x)
 and 
lim x→a+ g(x)
 both exist but 
lim x→a g(x)
 does not exist.
smaller valuea= larger valuea
(d)
lim x→a+ g(x) = g(a)
 but 
lim x→a g(x) ≠ g(a).
a =  
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