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For the function y 8 f(æ) = 1+ x² ' a. Find the slope of the line tangent to its inverse function at the point P(4, 1): m = -16 X o -0.25 b. Find the equation of the line tangent to the inverse function at the point P(4, 1): 1 Y = X o - 0.25x + 1+ 0.25 ·4 -16x-3

For the function y 8 f(æ) = 1+ x² ' a. Find the slope of the line tangent to its inverse function at the point P(4, 1): m = -16 X o -0.25 b. Find the equation of the line tangent to the inverse function at the point P(4, 1): 1 Y = X o - 0.25x + 1+ 0.25 ·4 -16x-3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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8 For the function y : f(x) : 1+ x² ' a. Find the slope of the line tangent to its inverse function at the point P(4, 1): т — -16 X o -0.25 b. Find the equation of the line tangent to the inverse function at the point P(4, 1): 1 y = X o – 0.25x + 1 + 0.25 ·4 -16х-3
Transcribed Image Text:8 For the function y : f(x) : 1+ x² ' a. Find the slope of the line tangent to its inverse function at the point P(4, 1): т — -16 X o -0.25 b. Find the equation of the line tangent to the inverse function at the point P(4, 1): 1 y = X o – 0.25x + 1 + 0.25 ·4 -16х-3
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