For the function given below use the first and second derivatives to identify the intervals of monotonicity (increasing/decreasing), relative extrema, intervals of concavity, and inflection points. f (x) = 2x3 + 3.x2 - 7 %3D
For the function given below use the first and second derivatives to identify the intervals of monotonicity (increasing/decreasing), relative extrema, intervals of concavity, and inflection points. f (x) = 2x3 + 3.x2 - 7 %3D
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Problem Statement:**
For the function given below, use the first and second derivatives to identify the intervals of monotonicity (increasing/decreasing), relative extrema, intervals of concavity, and inflection points.
\[ f(x) = 2x^3 + 3x^2 - 7 \]
**Solution Approach:**
1. **First Derivative Analysis**:
- Find \( f'(x) \) to determine intervals of increasing and decreasing behavior of the function.
2. **Critical Points and Relative Extrema**:
- Identify the critical points by setting \( f'(x) = 0 \) and solving for \( x \). Use these points to find relative maxima and minima.
3. **Second Derivative Analysis**:
- Calculate \( f''(x) \) to analyze concavity and find inflection points.
4. **Intervals of Concavity**:
- Determine where \( f''(x) > 0 \) (concave up) and where \( f''(x) < 0 \) (concave down).
5. **Inflection Points**:
- Identify points where \( f''(x) = 0 \) and a change in concavity occurs.
By using these steps, you can comprehensively understand the behavior of the function \( f(x) = 2x^3 + 3x^2 - 7 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F90a33a58-2d17-40a7-8fb2-1eb349f61a9b%2F742d060b-c9ed-4f68-88c2-5118b7b7fc37%2Fwwdk64v_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
For the function given below, use the first and second derivatives to identify the intervals of monotonicity (increasing/decreasing), relative extrema, intervals of concavity, and inflection points.
\[ f(x) = 2x^3 + 3x^2 - 7 \]
**Solution Approach:**
1. **First Derivative Analysis**:
- Find \( f'(x) \) to determine intervals of increasing and decreasing behavior of the function.
2. **Critical Points and Relative Extrema**:
- Identify the critical points by setting \( f'(x) = 0 \) and solving for \( x \). Use these points to find relative maxima and minima.
3. **Second Derivative Analysis**:
- Calculate \( f''(x) \) to analyze concavity and find inflection points.
4. **Intervals of Concavity**:
- Determine where \( f''(x) > 0 \) (concave up) and where \( f''(x) < 0 \) (concave down).
5. **Inflection Points**:
- Identify points where \( f''(x) = 0 \) and a change in concavity occurs.
By using these steps, you can comprehensively understand the behavior of the function \( f(x) = 2x^3 + 3x^2 - 7 \).
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