For the function given below, find a formula for the Riemann sum obtained by dividing the interval (a,b) into n equal subintervals and using the right-hand endpoint for each c. Then take a limit of this sum as n o to calculate the area under the curve over (a,b) f(x) = 4x over the interval (0,3). Find a formula for the Riemann sum The area under curve over (0,3] is O square units. (Simplify your answer.)
For the function given below, find a formula for the Riemann sum obtained by dividing the interval (a,b) into n equal subintervals and using the right-hand endpoint for each c. Then take a limit of this sum as n o to calculate the area under the curve over (a,b) f(x) = 4x over the interval (0,3). Find a formula for the Riemann sum The area under curve over (0,3] is O square units. (Simplify your answer.)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 67E
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![For the function given below, find a formula for the Riemann sum obtained by dividing the interval [a,b] into n equal subintervals and using the right-hand endpoint for each c. Then take a limit of this sum as n → o to calculate the area under the curve over [a,b).
f(x) = 4x over the interval [0,3].
Find a formula for the Riemann sum.
S, =
The area under the curve over [0,3] is
square units.
(Simplify your answer.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0f7775f3-edad-4f27-ba1b-f7886a7505bd%2F918ed8c3-cf99-4832-8902-7093571ccdf3%2Fj56f99h_processed.png&w=3840&q=75)
Transcribed Image Text:For the function given below, find a formula for the Riemann sum obtained by dividing the interval [a,b] into n equal subintervals and using the right-hand endpoint for each c. Then take a limit of this sum as n → o to calculate the area under the curve over [a,b).
f(x) = 4x over the interval [0,3].
Find a formula for the Riemann sum.
S, =
The area under the curve over [0,3] is
square units.
(Simplify your answer.)
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