For the function f(x) = In(x + 1), let ro = 1, 1= 1.25, 22= 1.6,the Lagrange interpolating polynomial of degree 2 is given by P2(x) = Lo(x)f(xo) + L1(x)ƒ(x1) + L2(x)f (#2) then Lo(x)f(xo) =? at z = 1.18 (use 3 digit rounding) O Lo(1.18)f(ro) = 0.136 O Lo(1.18) f(x0) = -0.323 O Lo(1.18)/(xo) – 0.075 O Lo(1.18)f(xo) = 0.340 O Lo(1.18) f(ro) = 0.196

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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For the function f(x) = In(r + 1), let ro = 1, #1 = 1.25, 2= 1.6,the Lagrange interpolating
polynomial of degree 2 is given by
%3D
P2(x) = Lo(x)f(xo) + L1(x)f(x1) + L2(x)f (*2) then Lo(x)f(xo) =? at r = 1.18 (use 3
digit rounding)
O Lo(1.18)f(xo) = 0.136
O Lo(1.18)f(xo) = -0.323
%3D
O Lo(1.18)/(20)
0.075
O Lo (1.18) f(xo) – 0.340
O Lo(1.18)f(ro) – 0.196
Transcribed Image Text:For the function f(x) = In(r + 1), let ro = 1, #1 = 1.25, 2= 1.6,the Lagrange interpolating polynomial of degree 2 is given by %3D P2(x) = Lo(x)f(xo) + L1(x)f(x1) + L2(x)f (*2) then Lo(x)f(xo) =? at r = 1.18 (use 3 digit rounding) O Lo(1.18)f(xo) = 0.136 O Lo(1.18)f(xo) = -0.323 %3D O Lo(1.18)/(20) 0.075 O Lo (1.18) f(xo) – 0.340 O Lo(1.18)f(ro) – 0.196
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