For the function f(r) = 6(1+r)5, find the value of the difference quotient and h = 0.1, 0.01 and 0.001 f(0.53) f(0.43) f(0.44) f(0.43) f(0.431) f(0.43) - .1 .01 .001 = f(r+h)-f(r) for r=0.43 h
For the function f(r) = 6(1+r)5, find the value of the difference quotient and h = 0.1, 0.01 and 0.001 f(0.53) f(0.43) f(0.44) f(0.43) f(0.431) f(0.43) - .1 .01 .001 = f(r+h)-f(r) for r=0.43 h
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![For the function \( f(r) = 6(1 + r)^5 \), find the value of the difference quotient
\[
\frac{f(r + h) - f(r)}{h}
\]
for \( r = 0.43 \) and \( h = 0.1, 0.01 \) and \( 0.001 \).
\[
\frac{f(0.53) - f(0.43)}{0.1} = \quad \quad \quad \quad \quad \quad
\]
\[
\frac{f(0.44) - f(0.43)}{0.01} = \quad \quad \quad \quad \quad \quad
\]
\[
\frac{f(0.431) - f(0.43)}{0.001} = \quad \quad \quad \quad \quad \quad
\]
Please substitute the respective \( h \) values and calculate the function values to complete the difference quotients.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf6bcca1-d77f-469d-8067-ac9f27c3130a%2F52372231-99a9-46d1-97ca-5ccb8233426e%2Fnldf1wj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the function \( f(r) = 6(1 + r)^5 \), find the value of the difference quotient
\[
\frac{f(r + h) - f(r)}{h}
\]
for \( r = 0.43 \) and \( h = 0.1, 0.01 \) and \( 0.001 \).
\[
\frac{f(0.53) - f(0.43)}{0.1} = \quad \quad \quad \quad \quad \quad
\]
\[
\frac{f(0.44) - f(0.43)}{0.01} = \quad \quad \quad \quad \quad \quad
\]
\[
\frac{f(0.431) - f(0.43)}{0.001} = \quad \quad \quad \quad \quad \quad
\]
Please substitute the respective \( h \) values and calculate the function values to complete the difference quotients.
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