For the function f (a) = -3-4 1+4+4 with f' (프) = (20+1)' 2(162+-35) (2x+1)* 8+13 f" () %3D intercepts (0, -4 ), (-1, 0), (4,0) A. Find all asymptotes (vertical, horizontal) B. Find any critical values C. Find the relative max/min points D. Find intervals of increase and decrease E. Find the intervals of concave up/concave down and any inflection points Vertical Asymptote: Horizontal 0

Q: Estimate f(2.98, –1.99) given that f(3, –2) = 2, f«(3, –2) -3 and fy(3, –2) = -4. = f(2.98, –1.99)

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Q: find the absolute extrema of the function f(x) = x^2 - 6x on the intervals [- 1,6], (3,7], (0, 6),…

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Q: f(x) =4x^3 -24x^2 -60x a. find all values of x that correspond to horizontal tangent lines. b.…

A: GIVEN FUNCTION  IS f(x)=4x3-24x2-60x   Now first order derivative be f'(x)=12x2-48x-60=0 Solution a:…

Q: d) increasing decreasing. (You may use maple. However, you must clearly show how you used the first…

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A: Topic = Functions

Q: On which interval(s) is the function h(t) = (−t^3) + 3(t^2) + 24t − 11 decreasing?

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Q: Use the graph of f(x) to find the interval where f''(x) > 0. Ⓡ 3- 2- 1- ms -5 -4 -3 -2 -1 1 3 4 5 A.…

A: Here we have given the curve of f(x)  Now to determine all x value where  f"(x) > 0

Q: let f(x) = 2x²-36x² + 20. Find the intervals where f is increasing. a) (-3,0)√(3, ~) b) (-3,0)0(0,3)…

A: Let To find the intervals where  is increasing.

Q: Use the graph of f(x) to find the interval where f''(x) > 0. -5 -4 -3 -2 -1 3- 2- 2 -3₂ 4 T 5 A.…

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Q: 15. For f (x) = x ^ 3 -12x + 10 the interval where f (x) is concave downward is: A. (0, ) b. (-00,…

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Q: Find the equation of the slant asymptote for the function f(x)=x^2-x/x-2 y=

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Q: = (F 1-2 f(z) = 3z² + 솔

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Q: For the curve x³ + y² + 2xy = 4x Find all the x-intercepts of the curve. Then for each x-intercept…

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Q: Let f(x) = f(-1) = = f(-5) = f(-6) = 8x - 2, -x², X ≤ -5 X > -5' Find f(-1), f(-5), and f(-6).

A: Solve the given function

Q: Ay Use the given graph of y = f(x) to evaluate the following. (a) f(-3) (b) f(2) (c) f(0) (d) f(-3)…

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Q: Choose the point that corresponds to t=-1 when x=t^2-4 and y=t+1/t (-3, 0) (-3, -2) (3, 2) (-5,…

A: Given,x=t2-4andy=t+1tat t=-1x=-12-4x=1-4x=-3andy=-1+1-1y=-1-1y=-2