For the frame shown below, where: L-5 m q=6 kN/m P=17 KN Compute the displacement at D in mm accurate to two decimal places. Take E = 200 KN/mm² and 1 = 700*106 mmª. Initially assume that the displacement is to the left. h=7 m L/2 L/2 D
For the frame shown below, where: L-5 m q=6 kN/m P=17 KN Compute the displacement at D in mm accurate to two decimal places. Take E = 200 KN/mm² and 1 = 700*106 mmª. Initially assume that the displacement is to the left. h=7 m L/2 L/2 D
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Hello,
I am calculating the displacement of this frame at point D using the unit load method. I have used superposition when calculating the BM diagrams for the applied load. The correct answer is -42.47mm but I am getting -33.89mm. Can someone please help identify where I am going wrong? Thanks
![For the frame shown below, where:
L=5 m
h
q=6 kN/m
Compute the displacement at D in mm accurate to two decimal places. Take E = 200 KN/mm² and 1 = 700*106 mm4. Initially assume that the displacement is to the left.
b
1
1
h=7 m
P=17 KN
L/2
L/2
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d23b2ff-c734-41be-8946-dc1e3f9cde0e%2F59c23e47-1f5e-4729-b7b3-d6bf9c45facb%2Fqcf4k3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the frame shown below, where:
L=5 m
h
q=6 kN/m
Compute the displacement at D in mm accurate to two decimal places. Take E = 200 KN/mm² and 1 = 700*106 mm4. Initially assume that the displacement is to the left.
b
1
1
h=7 m
P=17 KN
L/2
L/2
D
![вкл
M
Le
dar
dola
2.5
-
Fu
है
144
M
1,17
T
EI
S
8
2.5
8
7
7
इ
Эт
-4745.125
200 x 100 x 700 xöt
m
21.25
[=1/3x7x147x3/4×7) - ( 1⁄2x144x5x7)
- (1/2₂x5X21.25×7)
=
= 33-89mm
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d23b2ff-c734-41be-8946-dc1e3f9cde0e%2F59c23e47-1f5e-4729-b7b3-d6bf9c45facb%2F4zel8c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:вкл
M
Le
dar
dola
2.5
-
Fu
है
144
M
1,17
T
EI
S
8
2.5
8
7
7
इ
Эт
-4745.125
200 x 100 x 700 xöt
m
21.25
[=1/3x7x147x3/4×7) - ( 1⁄2x144x5x7)
- (1/2₂x5X21.25×7)
=
= 33-89mm
M
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