For the frame loaded as shown, draw the complete and correct FBDs of the following: whole frame, member BE, member HK, pulley D, pulley J, member CDEHJ without the pulleys, and pin B. If block G weighs 133 N, determine all the forces acting on member CDEHJ (i.e. Cx, Cy, Dx, Dy, FBE, FHK, Jx and Jy). Also, calculate the horizontal (ABCBx) and vertical (ABCBy) components of the reactions between member ABC and pin B. 0.50 m 0.50 m 0.20 m 0.32 m R 0.12 m, 50⁰ B E 0.35 m 77 N 0.35 m H J R = 0.12 m

For the frame loaded as shown, draw the complete and correct FBDs of the following: whole frame, member BE, member HK, pulley D, pulley J, member CDEHJ without the pulleys, and pin B. If block G weighs 133 N, determine all the forces acting on member CDEHJ (i.e. Cx, Cy, Dx, Dy, FBE, FHK, Jx and Jy). Also, calculate the horizontal (ABCBx) and vertical (ABCBy) components of the reactions between member ABC and pin B. 0.50 m 0.50 m 0.20 m 0.32 m R 0.12 m, 50⁰ B E 0.35 m 77 N 0.35 m H J R = 0.12 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

ALREADY ANSWERED IN BARTLEBY. DO NOT COPY! (ENGINERRING MECHANICS) DRAW THE COMPLETE FREE-BODY DIAGRAM. UPVOTE WILL BE GIVEN. PLEASE WRITE THE COMPLETE SOLUTIONS. SOLVE IN 6 DECIMAL PLACES. BOX THE FINAL ANSWERS.)

For the frame loaded as shown, draw the complete and correct FBDs of the
following: whole frame, member BE, member HK, pulley D, pulley J, member CDEHJ
without the pulleys, and pin B. If block G weighs 133 N, determine all the forces
acting on member CDEHJ (i.e. Cx, Cy, Dx, Dy, FBE, FHK, Jx and Jy). Also, calculate the
horizontal (ABCBx) and vertical (ABCBy) components of the reactions between
member ABC and pin B.
0.50 m
0.85 m
0.50 m
R = 0.12 m
7
0.20 m 0.32 m 0.35 m
50°
77 N
0.35 m
H
-R = 0.12 m
J
G
0.10 m

Branch of science that deals with the stationary and moving bodies under the influence of forces.

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Step 1: Given Data

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Step 2: Reaction R(K) & F(HK) force

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Step 3: Pulley D & J

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Step 4: Member CDEFJ

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Step 5: FBDs of BE & pin B

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