For the following vector v, find |lull, the unit vector with the same direction angle as v. v = -i + 3j

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
### Finding the Unit Vector in the Same Direction as a Given Vector

#### Problem Statement:

For the following vector \( v \), find \(\|u\|\), the unit vector with the same direction angle as \( v \).

\[ v = -i + 3j \]

#### Options:

\[ 
\begin{array}{ll}
\text{(A)} & \mathbf{u} = \left( -\frac{\sqrt{10}}{10}, \frac{3\sqrt{10}}{10} \right) \\
\text{(B)} & \mathbf{u} = \left( -\frac{1}{2}, \frac{3}{2} \right) \\
\text{(C)} & \mathbf{u} = \left( -\frac{3}{\sqrt{2}}, \frac{1}{\sqrt{2}} \right) \\
\text{(D)} & \mathbf{u} = \left( -\frac{3\sqrt{10}}{10}, \frac{\sqrt{10}}{10} \right) \\
\end{array}
\]

#### Instructions:

To find the unit vector \( \mathbf{u} \) with the same direction as \( v \), follow these steps:

1. **Calculate the Magnitude of \( v \):**

   The vector \( v \) has components \( v = -1i + 3j \). The magnitude \(\|v\|\) is calculated as:

   \[
   \|v\| = \sqrt{(-1)^2 + 3^2} = \sqrt{1 + 9} = \sqrt{10}
   \]

2. **Determine the Unit Vector \( \mathbf{u} \):**

   The unit vector in the same direction as \( v \) is:

   \[
   \mathbf{u} = \frac{1}{\|v\|} v = \frac{1}{\sqrt{10}}(-i + 3j) = \left( -\frac{1}{\sqrt{10}}, \frac{3}{\sqrt{10}} \right)
   \]
   
   This can also be rationalized to:

   \[
   \mathbf{u} = \left( -\frac{\sqrt{10}}{10}, \frac{3
Transcribed Image Text:### Finding the Unit Vector in the Same Direction as a Given Vector #### Problem Statement: For the following vector \( v \), find \(\|u\|\), the unit vector with the same direction angle as \( v \). \[ v = -i + 3j \] #### Options: \[ \begin{array}{ll} \text{(A)} & \mathbf{u} = \left( -\frac{\sqrt{10}}{10}, \frac{3\sqrt{10}}{10} \right) \\ \text{(B)} & \mathbf{u} = \left( -\frac{1}{2}, \frac{3}{2} \right) \\ \text{(C)} & \mathbf{u} = \left( -\frac{3}{\sqrt{2}}, \frac{1}{\sqrt{2}} \right) \\ \text{(D)} & \mathbf{u} = \left( -\frac{3\sqrt{10}}{10}, \frac{\sqrt{10}}{10} \right) \\ \end{array} \] #### Instructions: To find the unit vector \( \mathbf{u} \) with the same direction as \( v \), follow these steps: 1. **Calculate the Magnitude of \( v \):** The vector \( v \) has components \( v = -1i + 3j \). The magnitude \(\|v\|\) is calculated as: \[ \|v\| = \sqrt{(-1)^2 + 3^2} = \sqrt{1 + 9} = \sqrt{10} \] 2. **Determine the Unit Vector \( \mathbf{u} \):** The unit vector in the same direction as \( v \) is: \[ \mathbf{u} = \frac{1}{\|v\|} v = \frac{1}{\sqrt{10}}(-i + 3j) = \left( -\frac{1}{\sqrt{10}}, \frac{3}{\sqrt{10}} \right) \] This can also be rationalized to: \[ \mathbf{u} = \left( -\frac{\sqrt{10}}{10}, \frac{3
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