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For the following three-phase system. R = 60 X, = 8N EAR = 150 V Vea V. ca ab 3-phase, 3-wire, Y-connected generator Phase sequence: ABC Iab X, = 8N R = 604 ECA = 150 V Z03 + Ipe X = 8 2 ll R = 62 Ice V be C EBC 150 V Z 02 a) Find the phase angles 0, and 0 [Ans: 0,= -120° and 0, = 120°] b) Find the current in each phase of the load. [Ans: c) Find the magnitude of the line currents. [Ans: 25.95 A] %3D 3' L= 15A2 – 53.13° ab I= 15A2 -173.13° I = 15A£66.87° bc ca ell

For the following three-phase system. R = 60 X, = 8N EAR = 150 V Vea V. ca ab 3-phase, 3-wire, Y-connected generator Phase sequence: ABC Iab X, = 8N R = 604 ECA = 150 V Z03 + Ipe X = 8 2 ll R = 62 Ice V be C EBC 150 V Z 02 a) Find the phase angles 0, and 0 [Ans: 0,= -120° and 0, = 120°] b) Find the current in each phase of the load. [Ans: c) Find the magnitude of the line currents. [Ans: 25.95 A] %3D 3' L= 15A2 – 53.13° ab I= 15A2 -173.13° I = 15A£66.87° bc ca ell

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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EXAMPLE 23.2 For the following three-phase system. a A R = 6 N X, = 8 N Vab Iab EAR = 150 V ° Vco Ica 3-phase, 3-wire, Y-connected generator Phase sequence: ABC X, = 8 N R = 6N ECA = 150 V Z 03 + R = 6N Ipe X, = 8 N ll b be + C EBC = 150 V Z02 a) Find the phase angles 0, and 0,- [Ans: 0,= -120° and 0,= 120°] b) Find the current in each phase of the load. [Ans: c) Find the magnitude of the line currents. [Ans: 25.95 A] 3* L= 15AL - 53.13° ab = 15AL -173.13° = 15A266.87° 3 eel
Transcribed Image Text:EXAMPLE 23.2 For the following three-phase system. a A R = 6 N X, = 8 N Vab Iab EAR = 150 V ° Vco Ica 3-phase, 3-wire, Y-connected generator Phase sequence: ABC X, = 8 N R = 6N ECA = 150 V Z 03 + R = 6N Ipe X, = 8 N ll b be + C EBC = 150 V Z02 a) Find the phase angles 0, and 0,- [Ans: 0,= -120° and 0,= 120°] b) Find the current in each phase of the load. [Ans: c) Find the magnitude of the line currents. [Ans: 25.95 A] 3* L= 15AL - 53.13° ab = 15AL -173.13° = 15A266.87° 3 eel
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