For the following system to be consistent, 7x- 5y + 3z + kz 82 -53x+31y 8x - 4y we must have, k - 3 6 3

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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For the following system to be consistent,

\[ 
\begin{align*}
7x - 5y + 3z &= 3 \\
-53x + 31y + kz &= 6 \\
8x - 4y - 8z &= -3
\end{align*}
\]

we must have \( k \neq \) [box for input].
Transcribed Image Text:For the following system to be consistent, \[ \begin{align*} 7x - 5y + 3z &= 3 \\ -53x + 31y + kz &= 6 \\ 8x - 4y - 8z &= -3 \end{align*} \] we must have \( k \neq \) [box for input].
Expert Solution
Step 1: Given system of equation:

The given system of equation is 

7 x minus 5 y plus 3 z equals 3
minus 53 x plus 31 y plus k z equals 6
8 x minus 4 y minus 8 z equals negative 3


Therefore the matrix form is AX=B

Where A equals open square brackets table row 7 cell negative 5 end cell 3 row cell negative 53 end cell 31 k row 8 cell negative 4 end cell cell negative 8 end cell end table close square brackets comma X equals open square brackets table row x row y row z end table close square brackets comma B equals open square brackets table row 3 row 6 row cell negative 3 end cell end table close square brackets.

Hence the augmented matrix is 

left square bracket A colon B right square bracket equals open square brackets table row 7 cell negative 5 end cell 3 vertical line 3 row cell negative 53 end cell 31 k vertical line 6 row 8 cell negative 4 end cell cell negative 8 end cell vertical line cell negative 3 end cell end table close square brackets


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