For the following system to be consistent, -1x₁ + 4x2 - 9x3 9 -3x1 + 7x2 + kx3 -2 -6x1 - 5x2 + 6x3 -4 = 2 we must have k 9 You may enter your answer as a fraction. X

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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### System of Linear Equations Consistency

To determine the conditions for the following system of linear equations to be consistent, the equations are given as:

1. \(-1x_1 + 4x_2 - 9x_3 = 9\)
2. \(-3x_1 + 7x_2 + kx_3 = -2\)
3. \(-6x_1 - 5x_2 + 6x_3 = 2\)

For the system to be consistent, it is stated that:

\[ k \neq -\frac{4}{9} \]

This means that the system will be inconsistent if \(k\) is equal to \(-\frac{4}{9}\).

### Instructions

You can enter your answer as a fraction to determine the value of \(k\) that maintains the system's consistency.

### Interface

A box is provided for inputting the value of \(k\). There is a "Check Answer" button below the input field, which allows you to verify your solution.
Transcribed Image Text:### System of Linear Equations Consistency To determine the conditions for the following system of linear equations to be consistent, the equations are given as: 1. \(-1x_1 + 4x_2 - 9x_3 = 9\) 2. \(-3x_1 + 7x_2 + kx_3 = -2\) 3. \(-6x_1 - 5x_2 + 6x_3 = 2\) For the system to be consistent, it is stated that: \[ k \neq -\frac{4}{9} \] This means that the system will be inconsistent if \(k\) is equal to \(-\frac{4}{9}\). ### Instructions You can enter your answer as a fraction to determine the value of \(k\) that maintains the system's consistency. ### Interface A box is provided for inputting the value of \(k\). There is a "Check Answer" button below the input field, which allows you to verify your solution.
Expert Solution
Step 1: Define the problem.

To determine the value of straight k, for which the following system is consistent.

table row cell negative 1 straight x subscript 1 plus 4 straight x subscript 2 minus 9 straight x subscript 3 end cell equals 9 row cell negative 3 straight x subscript 1 plus 7 straight x subscript 2 plus kx subscript 3 end cell equals cell negative 2 end cell row cell negative 6 straight x subscript 1 minus 5 straight x subscript 2 plus 6 straight x subscript 3 end cell equals 2 end table

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