For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population. The word counts of five essays are 500, 628, 544, 611, and 584. Use a sample size of 2. The mean of the population is (Round to two decimal places as needed.) The standard deviation of the population is . (Round to two decimal places as needed.) Identify all samples of size 2 with the correct accompanying means below. OA. 544, 500, x = 522 O B. 584, 584, x= 584 O C. 500, 628, x = 564 O D. 611, 628, x= 543.5 O E. 500, 584, x = 542 O F. 611, 544, x = 577.5 O G. 628, 584, x= 606 O H. 628, 544, x= 586 OI. 628, 611, x= 619.5 O J. 611, 611, x=611 O K. 500, 500, x = 500 OL. 611, 584, x = 597.5 O M. 544, 584, x 564 O N. 500, 544, x= 522 O o. 544, 544, x = 544 Click to select your answer(s). 2030 Rearson Education Inc. All rights reserved. Terms of Use | Privacy Policy |

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**Educational Content: Sampling Distribution Exercise**

For this exercise, you are tasked with finding the mean and standard deviation of a population. Using the given word counts of five essays: 500, 628, 544, 611, and 584, perform the following:

1. Calculate the mean and standard deviation of the population. 
   - **Mean of the population:** (Round to two decimal places as needed.)
   - **Standard deviation of the population:** (Round to two decimal places as needed.)

2. List all possible samples of size 2 (with replacement) from this population, and find the mean of each sample.

Below are the samples with their corresponding means (denoted as x̄). Identify all correct pairs:

- A. 544, 500, x̄ = 522
- B. 584, 584, x̄ = 584
- C. 500, 628, x̄ = 564
- D. 544, 584, x̄ = 564
- E. 500, 500, x̄ = 500
- F. 611, 544, x̄ = 577.5
- G. 628, 584, x̄ = 606
- H. 628, 611, x̄ = 619.5
- I. 500, 544, x̄ = 522
- J. 611, 611, x̄ = 611
- K. 500, 500, x̄ = 500
- L. 611, 584, x̄ = 597.5
- M. 544, 584, x̄ = 564
- O. 544, 544, x̄ = 544

Click to select your answer(s).

This exercise helps in understanding the concept of a sampling distribution and comparing it with the population's statistical parameters.
Transcribed Image Text:**Educational Content: Sampling Distribution Exercise** For this exercise, you are tasked with finding the mean and standard deviation of a population. Using the given word counts of five essays: 500, 628, 544, 611, and 584, perform the following: 1. Calculate the mean and standard deviation of the population. - **Mean of the population:** (Round to two decimal places as needed.) - **Standard deviation of the population:** (Round to two decimal places as needed.) 2. List all possible samples of size 2 (with replacement) from this population, and find the mean of each sample. Below are the samples with their corresponding means (denoted as x̄). Identify all correct pairs: - A. 544, 500, x̄ = 522 - B. 584, 584, x̄ = 584 - C. 500, 628, x̄ = 564 - D. 544, 584, x̄ = 564 - E. 500, 500, x̄ = 500 - F. 611, 544, x̄ = 577.5 - G. 628, 584, x̄ = 606 - H. 628, 611, x̄ = 619.5 - I. 500, 544, x̄ = 522 - J. 611, 611, x̄ = 611 - K. 500, 500, x̄ = 500 - L. 611, 584, x̄ = 597.5 - M. 544, 584, x̄ = 564 - O. 544, 544, x̄ = 544 Click to select your answer(s). This exercise helps in understanding the concept of a sampling distribution and comparing it with the population's statistical parameters.
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