For the following reaction, use the plots below and the information on them to determine the half-life (in s) of this reaction: Reaction: 2NO₂ (g) → 2NO (g) + O2 (8) Raw Data 0.015 € 0.01 y = -2E-05x +0.0084 R² = 0.8627 0.005 0 0 200 400 Time (s) In[NO2] vs Time 200 400 y = -0.0036x-4.744 R² = 0.9644 mo Time (s) [NO2] (M) In[NO2] -2 -6 -8
For the following reaction, use the plots below and the information on them to determine the half-life (in s) of this reaction: Reaction: 2NO₂ (g) → 2NO (g) + O2 (8) Raw Data 0.015 € 0.01 y = -2E-05x +0.0084 R² = 0.8627 0.005 0 0 200 400 Time (s) In[NO2] vs Time 200 400 y = -0.0036x-4.744 R² = 0.9644 mo Time (s) [NO2] (M) In[NO2] -2 -6 -8
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
A.) 0.193 s
B.) 64.4 s
C.) 129 s
D.) 193 s
![For the following reaction, use the plots below and the information on them to
determine the half-life (in s) of this reaction:
Reaction: 2NO₂ (g) → 2NO(g) + O₂ (g)
Raw Data
0.015
0.01
y = -2E-05x +0.0084
R² = 0.8627
0.005
0
0
200
400
Time (s)
In [NO2] vs Time
200
400
y = -0.0036x-4.744
R² = 0.9644
[NO2] (M)
In[NO2]
0
-2
-4
-6
-8
Time (s)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb1ca4019-f596-47d0-9ac7-d83eaf834e41%2F4b8a426a-43c3-4553-a5cd-cf48cee49fbb%2F354clc_processed.png&w=3840&q=75)
Transcribed Image Text:For the following reaction, use the plots below and the information on them to
determine the half-life (in s) of this reaction:
Reaction: 2NO₂ (g) → 2NO(g) + O₂ (g)
Raw Data
0.015
0.01
y = -2E-05x +0.0084
R² = 0.8627
0.005
0
0
200
400
Time (s)
In [NO2] vs Time
200
400
y = -0.0036x-4.744
R² = 0.9644
[NO2] (M)
In[NO2]
0
-2
-4
-6
-8
Time (s)
![1/[NO2]
400
300
200
100
0
1/[NO2] vs Time
0
y = 0.775x + 99.786
R² = 1
200
Time (s)
400](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb1ca4019-f596-47d0-9ac7-d83eaf834e41%2F4b8a426a-43c3-4553-a5cd-cf48cee49fbb%2Frx2lkhc_processed.png&w=3840&q=75)
Transcribed Image Text:1/[NO2]
400
300
200
100
0
1/[NO2] vs Time
0
y = 0.775x + 99.786
R² = 1
200
Time (s)
400
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