For the following reaction of protein dimerization. 2P → P. the concentration of protein monomer, P, in the aqueous solution at time zero was 0.2x10 mol L and at time 200 s the concentration was 0.02x10 3 mol L1. Calculate the reaction rate constant k. Select the closest value. 225 s-1 mol L-1 O 5s1 mol1 L 0.5 s1 mol 1 L2 0.02 s1 mol L'1 14.6 s1 mol L O 53 s1 mor1 O53x 103s1 mol? O024 x 10 s1 mol 2
For the following reaction of protein dimerization. 2P → P. the concentration of protein monomer, P, in the aqueous solution at time zero was 0.2x10 mol L and at time 200 s the concentration was 0.02x10 3 mol L1. Calculate the reaction rate constant k. Select the closest value. 225 s-1 mol L-1 O 5s1 mol1 L 0.5 s1 mol 1 L2 0.02 s1 mol L'1 14.6 s1 mol L O 53 s1 mor1 O53x 103s1 mol? O024 x 10 s1 mol 2
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section11.1: Reaction Rate
Problem 11.1PSP: For the reaction of crystal violet with NaOH(aq), the measured rate of reaction is 1.27 106 mol L1...
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![For the following reaction of protein dimerization, 2P P. the concentration of protein monomer, P, in
the aqueous solution at time zero was 0.2x10 mol L and at time 200 s the concentration was
0.02x10 3 mol L1. Calculate the reaction rate constant k. Select the closest value.
225 s-1 mol L-1
O 5s1 mol1 L
O0.5 s1 mol1 L2
O 0.02 s1 mol L·1
O 14.6 s´1 mol L
GD 53 s1 mo1
O53x 10 s1 mol 2
0.24 x 10 s1 mol 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc052dae8-d4f9-4c1e-9a92-f7b9167ef9ed%2Fd574ba28-bfec-4ed5-9c5c-9e358740b757%2F87ltkz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the following reaction of protein dimerization, 2P P. the concentration of protein monomer, P, in
the aqueous solution at time zero was 0.2x10 mol L and at time 200 s the concentration was
0.02x10 3 mol L1. Calculate the reaction rate constant k. Select the closest value.
225 s-1 mol L-1
O 5s1 mol1 L
O0.5 s1 mol1 L2
O 0.02 s1 mol L·1
O 14.6 s´1 mol L
GD 53 s1 mo1
O53x 10 s1 mol 2
0.24 x 10 s1 mol 2
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