For the following reaction 302(g) = 203(g) Kc = 2.10 × 10¬7 at a certain temperature. If [O2] = 0.0495 M when at equilibrium, what is the equilibrium O3 concentration? %3D

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Chemical Equilibrium Problem**

**For the following reaction:**

\[ 3O_2(g) \rightleftharpoons 2O_3(g) \]

**Equilibrium Constant:**

\[ K_c = 2.10 \times 10^{-7} \] 
(at a certain temperature)

**Given Information:**

\[ [O_2] = 0.0495 \, \text{M} \]
(at equilibrium)

**Problem:**

What is the equilibrium concentration of \(\text{O}_3\)?

This problem requires calculating the equilibrium concentration of ozone \((\text{O}_3)\) using the given equilibrium concentration of oxygen \((\text{O}_2)\) and the equilibrium constant \(K_c\).
Transcribed Image Text:**Chemical Equilibrium Problem** **For the following reaction:** \[ 3O_2(g) \rightleftharpoons 2O_3(g) \] **Equilibrium Constant:** \[ K_c = 2.10 \times 10^{-7} \] (at a certain temperature) **Given Information:** \[ [O_2] = 0.0495 \, \text{M} \] (at equilibrium) **Problem:** What is the equilibrium concentration of \(\text{O}_3\)? This problem requires calculating the equilibrium concentration of ozone \((\text{O}_3)\) using the given equilibrium concentration of oxygen \((\text{O}_2)\) and the equilibrium constant \(K_c\).
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