For the following questions, you do not need to understand the physics. Just focus on working with the equations: To enter subscripts, press the first right-facing arrow by the superscript button in the menu of the popup. (a) Two resistors R₁ and R₂ in an electric circuit are connected in parallel. The effective resistance of the circuit is given by: (Simplify as much as possible and express the answer as a fraction.) 1 1 1 = + R R₁ R₂ Solve for R in terms of R₁ and R₂: R= (b) The volume of a sphere of radius R is V= much as possible. R= 4 πR³ 3 Solve for R in terms of π and V. Simplify as

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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1. For the following questions, you do not need to understand the physics. Just focus on working with
the equations:
To enter subscripts, press the first right-facing arrow by the superscript button in the menu of
the popup.
(a) Two resistors R₁ and R₂ in an electric circuit are connected in parallel. The effective resistance
of the circuit is given by:
(Simplify as much as possible and express the answer as a fraction.)
1 1 1
+
R R₁ R₂
Solve for R in terms of R₁ and R₂:
R=
=
(b) The volume of a sphere of radius R is V=
much as possible.
R =
✓
4 πR³
3
Solve for R in terms of and V. Simplify as
Transcribed Image Text:1. For the following questions, you do not need to understand the physics. Just focus on working with the equations: To enter subscripts, press the first right-facing arrow by the superscript button in the menu of the popup. (a) Two resistors R₁ and R₂ in an electric circuit are connected in parallel. The effective resistance of the circuit is given by: (Simplify as much as possible and express the answer as a fraction.) 1 1 1 + R R₁ R₂ Solve for R in terms of R₁ and R₂: R= = (b) The volume of a sphere of radius R is V= much as possible. R = ✓ 4 πR³ 3 Solve for R in terms of and V. Simplify as
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