For the following questions assume that the acceleration due to gravity, g, is equal to 10 m/s2 Also, take the upward direction to be positive and the downward direction to be negative. This will be important for the sign of your velocity in the answers below. You only need to indicate a sign if the value is negative. A ball is thrown straight up with enough speed so that it is in the air for several seconds. 1) What is the velocity of the ball when it reaches its highest point? (a) 10 m/s2 (b) -10 m/s2 (c) 0 m/s2 2) What is its velocity 1 s before it reaches its highest point? (a) 10 m/s2 (b) -10 m/s2 (c) 0 m/s2 3) What is the change in its velocity during this 1-s interval? (In other words, what is the change in velocity during the time interval of 1 second before reaching its highest point? Don't forget that change in velocity is equal to the final velocity (at the highest point) minus the starting velocity (velocity 1 second before reaching the highest point). (a) 10 m/s2 (b) -10 m/s2 (c) 0 m/s2 4) What is its velocity 1 s after it reaches its highest point? The ball is now on its way back down. (a) 10 m/s2 (b) -10 m/s2 (c) 0 m/s2 5) What is the change in its velocity during this 1-s interval? (This would be the final velocity (1 second after reaching its highest point) minus the initial velocity (velocity the highest point). (a) 10 m/s2 (b) -10 m/s2 (c) 0 m/s2 6) What is the change in velocity during the 2-s interval from 1 s before the highest point to 1 s after the highest point? This would be the final velocity at a point one second after reaching the highest point (answer for part d) minus the initial velocity at a point one second before reaching the highest point (answer for part b). Answer: - 20 m/s What is the acceleration of the ball during any of these time intervals and at the moment the ball has zero velocity? Remember that acceleration is a measure of how the velocity changes with time. average acceleration = change in velocity time (a) 10 m/s2 (b) -10 m/s2 (c) 0 m/s2
For the following questions assume that the acceleration due to gravity, g, is equal to 10 m/s2 Also, take the upward direction to be positive and the downward direction to be negative. This will be important for the sign of your velocity in the answers below. You only need to indicate a sign if the value is negative.
A ball is thrown straight up with enough speed so that it is in the air for several seconds.
1) What is the velocity of the ball when it reaches its highest point?
(a) 10 m/s2
(b) -10 m/s2
(c) 0 m/s2
2) What is its velocity 1 s before it reaches its highest point?
(a) 10 m/s2
(b) -10 m/s2
(c) 0 m/s2
3) What is the change in its velocity during this 1-s interval? (In other words, what is the change in velocity during the time interval of 1 second before reaching its highest point? Don't forget that change in velocity is equal to the final velocity (at the highest point) minus the starting velocity (velocity 1 second before reaching the highest point).
(a) 10 m/s2
(b) -10 m/s2
(c) 0 m/s2
4) What is its velocity 1 s after it reaches its highest point? The ball is now on its way back down.
(a) 10 m/s2
(b) -10 m/s2
(c) 0 m/s2
5) What is the change in its velocity during this 1-s interval? (This would be the final velocity (1 second after reaching its highest point) minus the initial velocity (velocity the highest point).
(a) 10 m/s2
(b) -10 m/s2
(c) 0 m/s2
6) What is the change in velocity during the 2-s interval from 1 s before the highest point to 1 s after the highest point? This would be the final velocity at a point one second after reaching the highest point (answer for part d) minus the initial velocity at a point one second before reaching the highest point (answer for part b). Answer: - 20 m/s
What is the acceleration of the ball during any of these time intervals and at the moment the ball has zero velocity? Remember that acceleration is a measure of how the velocity changes with time.
average acceleration =
| change in velocity |
| time |
(a) 10 m/s2
(b) -10 m/s2
(c) 0 m/s2
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