For the following letter frequency table, a Huffman Code was constructed as shown below. The associated tree is also shown below. Letter L 42 110 Frequency Huffman Code E 120 1 0 306 D 42 101 79 1 0 1 (186 U 37 100 1 0 107 0 C 32 1110 65 M 24 11111 K 7 111101 Z 2 111100 (a) Is there another code and a tree possible? What is (are) the difference(s)? (b) Compute the redundancy= Average Codeword Length (Lav) - Entropy (H(x)). The entropy H(x) is calculated from H(x) = -=1 Pilogpi- (c) Check if this redundancy is less than p₁ +0.086, where p₁ is the probability of the most common symbol. (d) Also, check if the following inequality is satisfied: H(x) ≤ Lav ≤ H(x) + 1. Repeat parts (b), (c), (d) for a different tree you built. What conclusions can you
For the following letter frequency table, a Huffman Code was constructed as shown below. The associated tree is also shown below. Letter L 42 110 Frequency Huffman Code E 120 1 0 306 D 42 101 79 1 0 1 (186 U 37 100 1 0 107 0 C 32 1110 65 M 24 11111 K 7 111101 Z 2 111100 (a) Is there another code and a tree possible? What is (are) the difference(s)? (b) Compute the redundancy= Average Codeword Length (Lav) - Entropy (H(x)). The entropy H(x) is calculated from H(x) = -=1 Pilogpi- (c) Check if this redundancy is less than p₁ +0.086, where p₁ is the probability of the most common symbol. (d) Also, check if the following inequality is satisfied: H(x) ≤ Lav ≤ H(x) + 1. Repeat parts (b), (c), (d) for a different tree you built. What conclusions can you
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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I would like to know if someone know the step by step process for this problem. Any help will be appreciated
Transcribed Image Text:For the following letter frequency table, a Huffman Code was constructed as shown
below. The associated tree is also shown below.
Letter
L
D
42
42
110 101
Frequency
Huffman Code
E
120
1
0
(306
79
1
0
1
186
U
37
100
42
1
0
107
C
32
1110
M
24
11111
K
7
111101
Z
2
111100
图园
(a) Is there another code and a free possible? What is (are) the difference(s)?
(b) Compute the redundancy = Average Codeword Length (Lav) - Entropy (H(x)).
The entropy H(x) is calculated from H(x) = -Ei=1 Pilogpi.
(c) Check if this redundancy is less than p₁ + 0.086, where p₁ is the probability of
the most common symbol.
(d) Also, check if the following inequality is satisfied:
H(x) ≤ Lav ≤H (x) + 1.
Repeat parts (b), (c), (d) for a different tree you built. What conclusions can you
drawe
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