None for the following I need you to check the molar absorbitivity. I used the wavelenghth for each. # 1 = 372nm, 2 = 370, nm3 = 370nm, 4 = 372nm. I changed nm to cm and got the molar absorbitity as shown. please if this is not correct, can youcorrect it and give the 95% confidence interval for a sample.دReport table 2: Determination of Molar absorptivity of K2CrO4ppm of K2CrO4 in "DILUTE STOCK (5mL/50mL)"=1.5012Molarity of K CrO in "DILUTE STOCK(5mL/50mL)" = 7.7319× 10^-3Peak wavelengthPeak AbsorbanceFrom spectrummax=372 nmA=0.4878=>1234A= 0.370A=0.434A=0.487A= 0.347From singlewavelengthvalues=8=1.2864×10^61.5171×10^61.7023×10 6 1.20642×10^6Average & (for the 4readings)Standard deviation of95% Confidence intervalof €=1.428055×10^6=2Show sample calculation (for solution 1): 2= A/b.c =Molar Absorption= 0,370/(3.72×10^-5)(7.7319× 10^-3)= 1.2864×10^6 M^-1 cm^-1

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for the following I need you to check the molar absorbitivity. I used the wavelenghth for each. #1 = 372nm, 2 = 370, nm 3 = 370nm, 4 =372nm. I changed nm to cm and got the molar absorbitity as shown. please if this is not correct, can you correct it and give the 95% confidence interval for a sample. Report table 2: Determination of Molar absorptivity of K2CrO4 ppm of K:CrO4 in "DILUTE STOCK (5mL/50mL)"=1.5012 Molarity of K CrO₁ in "DILUTE STOCK(5mL/50mL)" = 7.7319× 10^-3 Peak wavelength Peak Absorbance From spectrum max=372 nm A=0.487 8= 1 2 3 A=0.434 A=0.487 A=0.347 From single wavelength values A=0.370 8= === 1.2864×10 6 1.5171×10^6 εm Ɛm 1.7023×10^6 1.20642×10^6 Average & (for the 4 readings) Standard deviation of ε 95% Confidence interval of E = 1.428055×10^6 =2 = Show sample calculation (for solution 1): = A/b.c = Molar Absorption= 0,370/(3.72×10^-5)(7.7319× 10^-3)= 1.2864×10^6 M^-1 cm^-1

for the following I need you to check the molar absorbitivity. I used the wavelenghth for each. #1 = 372nm, 2 = 370, nm 3 = 370nm, 4 =372nm. I changed nm to cm and got the molar absorbitity as shown. please if this is not correct, can you correct it and give the 95% confidence interval for a sample. Report table 2: Determination of Molar absorptivity of K2CrO4 ppm of K:CrO4 in "DILUTE STOCK (5mL/50mL)"=1.5012 Molarity of K CrO₁ in "DILUTE STOCK(5mL/50mL)" = 7.7319× 10^-3 Peak wavelength Peak Absorbance From spectrum max=372 nm A=0.487 8= 1 2 3 A=0.434 A=0.487 A=0.347 From single wavelength values A=0.370 8= === 1.2864×10 6 1.5171×10^6 εm Ɛm 1.7023×10^6 1.20642×10^6 Average & (for the 4 readings) Standard deviation of ε 95% Confidence interval of E = 1.428055×10^6 =2 = Show sample calculation (for solution 1): = A/b.c = Molar Absorption= 0,370/(3.72×10^-5)(7.7319× 10^-3)= 1.2864×10^6 M^-1 cm^-1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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