For the following function, find the Taylor series centered at x = of the Taylor series and the open interval of convergence. 3πT and then give the first 5 nonzero terms 2 f(x) = sin(x) f(x) = Σ n=0 8 f(x) = −1+ 1½ ( x − 3 x ) 2 1 3π 2 24 -2(x-3) 4 + 710 (x-3)6 3π x- 2 2 40320 The open interval of convergence is: (-00,00) (Give your answer in help (intervals).)

For the following function, find the Taylor series centered at x = of the Taylor series and the open interval of convergence. 3πT and then give the first 5 nonzero terms 2 f(x) = sin(x) f(x) = Σ n=0 8 f(x) = −1+ 1½ ( x − 3 x ) 2 1 3π 2 24 -2(x-3) 4 + 710 (x-3)6 3π x- 2 2 40320 The open interval of convergence is: (-00,00) (Give your answer in help (intervals).)

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Hi, can you tell me if the following is true or false?
6.4 Suppose that n =0 anx" has an interval of convergence of (-1, 1). Find the interval of convergence of Σ.3.
(a)Find the radius. I I totally got -1. Is that correct? (b) what is the interval of convergence. I got (-1,1) but it is wrong.
. By using the definition of convergence, show that lim ( =) = 0. Or in other words, what can we take for N?
I need help with finding if this converges or diverges
#1. Thanks.
(4) Suppose {a„}1 converges to L and that a, 2 0 for all n. Prove that {Van}1 converges to L. Tip: Note that by problem (2), L > 0. For the case L = 0, you can just cite the previous problem. Finally, for the case L > 0, use (Van – VL)(yan + VL) = a, – L to deduce that n=1 lan – L. IVan – VI| < VL
I got R=1/3 and it is incorrect