For the following function, find the Taylor series centered at x = of the Taylor series and the open interval of convergence. 3πT and then give the first 5 nonzero terms 2 f(x) = sin(x) f(x) = Σ n=0 8 f(x) = −1+ 1½ ( x − 3 x ) 2 1 3π 2 24 -2(x-3) 4 + 710 (x-3)6 3π x- 2 2 40320 The open interval of convergence is: (-00,00) (Give your answer in help (intervals).)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(I already have the Taylor expansion and the interval of convergence correct) I just need the first part and I'm not quite sure what it is asking me. I know it doesn't use "f" because it says it is not defined in this context.

For the following function, find the Taylor series centered at x =
of the Taylor series and the open interval of convergence.
3πT
and then give the first 5 nonzero terms
2
f(x) = sin(x)
f(x)
=
Σ
n=0
8
f(x)
=
−1+
1½ ( x − 3 x ) 2
1
3π
2
24
-2(x-3) 4 + 710 (x-3)6
3π
x-
2
2
40320
The open interval of convergence is: (-00,00) (Give your answer in help (intervals).)
Transcribed Image Text:For the following function, find the Taylor series centered at x = of the Taylor series and the open interval of convergence. 3πT and then give the first 5 nonzero terms 2 f(x) = sin(x) f(x) = Σ n=0 8 f(x) = −1+ 1½ ( x − 3 x ) 2 1 3π 2 24 -2(x-3) 4 + 710 (x-3)6 3π x- 2 2 40320 The open interval of convergence is: (-00,00) (Give your answer in help (intervals).)
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